All categories

3 years ago

Please help bffbgfg5vrvtvt

Physics

1 answer:

Anvisha [2.4K]3 years ago

7 0

Answer:

B) converging tectonic plates

Explanation:

You might be interested in

What three forces are always in effect?

natka813 [3]

Answer:The gravitational force is defined in Uniform Circular Motion and Gravitation, electric force in Electric Charge and Electric Field, magnetic force in Magnetism, and nuclear forces in Radioactivity and Nuclear Physics. On a macroscopic scale, electromagnetism and gravity are the basis for all forces.

Explanation:

7 0

3 years ago

Read 2 more answers

Help help hep help???????????

Sergeu [11.5K]

Momentum

mava + mbvb = mava '+ mbvb'

(300 x 10)+(150 x 0) = (300 x 4.12)+(150 x vb')

3000=1236+150vb'

1764 = 150vb'

vb'=+11.76 m/s ≈ +11.8 m/s (positive sign, to the right)

3 0

2 years ago

Please, Help!!

Elenna [48]

Let, 1st force = a

2nd force = b

A.T.Q,

a+b = 10

a-b = 6

Calculate for a & b, you'll get a=8 & b= 2

After increasing by 3, it'll be a = 8+3 = 11 & b=2+3 = 5

Resultant force at 90 degree angle = 11+5 = 16 Newtons

7 0

3 years ago

Read 2 more answers

How can you find average speed

BabaBlast [244]

Average speed =

(total distance covered)

divided by

(total time spent covering the distance)

4 0

3 years ago

A cricket ball has mass 0.155 kg. If the velocity of a bowled ball has a magnitude of 35.0 m/s and the batted ball's velocity is

FinnZ [79.3K]

Answer:

Magnitude of change in momentum = 4.65 kg.m/s

Magnitude of impulse = 4.65 kg.m/s

Magnitude of the average force applied by the bat = 1550 N

Explanation:

Mass of the cricket ball, m = 0.155 kg

Initial velocity of the ball, u = 35.0 m/s

final velocity of the ball after hitting the bat, v = 65.0 m/s

Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s

Now,

Magnitude of change in momentum = Final momentum - Initial momentum

Magnitude of change in momentum = ( m × v ) - ( m × u )

Magnitude of change in momentum = ( 0.155 × 65 ) - ( 0.155 × 35 )

Magnitude of change in momentum = 10.075 - 5.425 = 4.65 kg.m/s

Now, Magnitude of impulse = change in momentum

thus,

Magnitude of impulse = 4.65 kg.m/s

Now,

magnitude of the average force applied by the bat = $\frac{\textup{Impulse}}{\textup{Time}}$

magnitude of the average force applied by the bat = $\frac{\textup{4.65}}{\textup{3}\times\textup{10}^{-3}}$

Magnitude of the average force applied by the bat = 1550 N

6 0

4 years ago