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1 year ago

PLEAS HELP ME OUT !!!!!!

Mathematics

2 answers:

Levart [38]1 year ago

6 0

Answer:

Step-by-step explanation:

If you look between the 8 and the twelve you see they went up by 4. Then you see they go up 2 each line. 8, 10, 12,14,16,18, therefore having the answer being 20.

Kamila [148]1 year ago

3 0

Answer:

Step-by-step explanation:

the number line is patterned in twos, so the dot will be at 20, since its 4 spaces away from 12

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Find the missing side of the right triangle. Side a = 10 and side b = 5

Levart [38]

Assuming that C is the hypotenuse...

The formula you want to use is:

a^2 + b^2 = c^2

We start by squaring 10, which is 100. 5^2 is 25. Now that we have the values, we can do the equation.

100+25=c^2 100+25= $\sqrt{125}$

Now, square root $\sqrt{125}$

C= 11.180

3 0

2 years ago

A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one

TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are $\binom44\binom{48}1=48$ possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by $\binom{13}1=13$ . So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

$\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024$

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing $\binom41\binom{48}4=778,320$ possible hands. Exactly 2 aces are drawn in $\binom42\binom{48}3=103,776$ hands. And so on. This gives a total of

$\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656$

possible hands containing at least 1 ace, and hence B occurs with probability

$\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412$

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. $P(A\cap B)=P(A)P(B)$ . This happens if

the hand has 4 aces and 1 non-ace, or
the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So $A\cap B$ consists of 96 possible hands, which occurs with probability

$\dfrac{96}{\binom{52}5}\approx0.0000369$

and so the events A and B are NOT independent.

4 0

3 years ago

Diane's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Diane

Shalnov [3]

4.05x+5.25(149-x)=710.25
Solve for x
X=60 ........4.05

149-60=89.....5.25

5 0

3 years ago

n a survey of 331 customers, 66 say that service is poor. You select two customers without replacement to get more information o

yaroslaw [1]

Answer:

3.93% probability that both say service is poor

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The customers are chosen without replacement, and the order in which they are chosen is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.