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kolezko [41]
3 years ago
13

As part of an investigation, students combined substances in a beaker to observe chemical reactions. They performed two procedur

es. They measured the mass of each substance before and after each reaction. The table shows their observations.
Assuming the students did not make any careless errors, what likely explains these changes in mass?

A. Procedure 1: All the reactants were liquids that evaporated.
Procedure 2: A gas was formed as one product, and it escaped into the air.

B. Procedure 1: One of the reactants was converted to thermal energy.
Procedure 2: All the products were liquids.

C. Procedure 1: The reactants were liquids with different densities.
Procedure 2: The reactants were combined into only one product.

D. Procedure 1: One of the products was a gas that escaped into the air.
Procedure 2: A gas from the air reacted with one of the other reactants.

Chemistry
2 answers:
asambeis [7]3 years ago
8 0

Answer:

D.

Explanation:

aniked [119]3 years ago
3 0

Answer: its D

Explanation: I took a test, got it correct.

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The pressure of a gas sample was measured to be 654 mmhg. What is the pressure in kpa? (1 atm = 1. 01325 × 10 5 pa)
Stels [109]

Taking into account the change of units, the pressure of the gas sample is 87.19 kPa.

<h3>What is rule of three</h3>

In first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.

To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: c=\frac{cxb}{a}

<h3>Pressure</h3>

The direct rule of three is the rule applied in this case where there is a change of units.

To perform in this case the conversion of units, you must first know that:

  • 1 atm= 760 mmHg
  • 1 atm = 1. 01325×10⁵ Pa= 101325 Pa
  • 1 kPa= 1000 Pa

So, if 1 atm is 760 mmHg, how many atm equals 654 mmHg?

760 mmHg ⇒ 1 atm

654 mmHg ⇒ x

So: x=\frac{654 mmHgx1 atm}{760 mmHg}

Solving:

<u><em>x=0.86 atm</em></u>

Now, if 101325 Pa are 1 atm, how many Pa equals 0.86 atm?

1 atm ⇒ 101325 Pa

0.86 atm ⇒ x

So: x=\frac{0.86 atmx101325 Pa}{1 atm}

Solving:

<u><em>x= 87,192.83 Pa</em></u>

Finally, if 1 kPa is 1000 Pa, how many kPa equals 87,192.83 Pa?

1000 Pa ⇒ 1 kPa

87,192.83 Pa ⇒ x

So: x=\frac{87,192.83 Pax1 kPa}{1000 Pa}

Solving:

<u><em>x=87.19283 kPa≅ 87.19 kPa</em></u>

In summary, the pressure of the gas sample is 87.19 kPa.

Learn more with this example:

brainly.com/question/12482948

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The radius of the large cylinder of a hydrolic press
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Answer: 1) 400N

2)1.6

Explanation:

1) 5cm = 100N of force

so

20cm=400n

2) 0.4 X 4 = 1.6

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3 years ago
Which of the following would form a cation? Ne Li O I
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A gas occupies 525 mL at a pressure of 45.0 kPa. What would the volume of the gas be at a pressure of 65.0 kPa
choli [55]

Answer:

The volume of the gas at a pressure of 65.0 kPa would be 363 mL

Explanation:

Boyle's Law is a gas law that relates the pressure and volume of a certain amount of gas, without temperature variation, that is, at constant temperature.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. In other words, the product P · V remains constant at the same temperature:

P*V=k

Being P1 and V1 the pressure and volume in state 1 and P2 and V2 the pressure and volume in state 2 are fulfilled:

P1*V1=P2*V2

In this case:

  • P1= 45 kPa= 45,000 Pa (being 1 kPa=1,000 Pa)
  • V1= 525 mL= 0.525 L (being 1 L=1,000 mL)
  • P2= 65 kPa= 65,000 Pa
  • V2= ?

Replacing:

45,000 Pa* 0.525 L= 65,000 Pa*V2

Solving:

V2=\frac{45,000 Pa* 0.525 L}{65,000 Pa}

V2=0.363 L=363 mL

<u><em>The volume of the gas at a pressure of 65.0 kPa would be 363 mL</em></u>

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which of the molecules listed below directly donates a nitrogen atom for the formation of urea during the urea cycle?
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Aspartate directly donates a nitrogen atom from the formation of urea during the urea cycle.
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