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kolezko [41]
2 years ago
13

As part of an investigation, students combined substances in a beaker to observe chemical reactions. They performed two procedur

es. They measured the mass of each substance before and after each reaction. The table shows their observations.
Assuming the students did not make any careless errors, what likely explains these changes in mass?

A. Procedure 1: All the reactants were liquids that evaporated.
Procedure 2: A gas was formed as one product, and it escaped into the air.

B. Procedure 1: One of the reactants was converted to thermal energy.
Procedure 2: All the products were liquids.

C. Procedure 1: The reactants were liquids with different densities.
Procedure 2: The reactants were combined into only one product.

D. Procedure 1: One of the products was a gas that escaped into the air.
Procedure 2: A gas from the air reacted with one of the other reactants.

Chemistry
2 answers:
asambeis [7]2 years ago
8 0

Answer:

D.

Explanation:

aniked [119]2 years ago
3 0

Answer: its D

Explanation: I took a test, got it correct.

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The number of moles of oxygen required to generate 28 moles of water from the reaction is 14 moles

<h3>Balanced equation </h3>

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

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<h3>How to determine the mole of oxygen needed </h3>

From the balanced equation above,

2 moles of water were obtained from 1 mole of oxygen

Therefore,

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Thus, 14 moles of oxygen are needed for the reaction

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Use the Ideal Gas Law to find the moles of gas first.

Be sure to convert T from Celsius to Kelvin by adding 273.

Also I prefer to deal with pressure in atm rather than mmHg, so divide the pressure by 760 to get it in atm.

PV = nRT —> n = PV/RT
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n = (0.720 atm)(1.90 L) / (0.08206 L atm / mol K)(306 K) = 0.0545 mol of gas

Now divide grams by mol to get the molecular weight.

3.42 g / 0.0545 mol = 62.8 g/mol
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