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2 years ago

5

The student lets the toy car roll down the slope. describe how the student could find, by experiment the speed of the toy car at

the bottom of the slope

1 answer:

soldier1979 [14.2K]2 years ago

7 0

Answer:

The student can experiment by timing the speed and changing the angle of the ramp for many number of trials.

Explanation:

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What is the gravity force between two stars with mass of 5,000,000 kg and 1,000,000 kg if the distance between them is 100 m

Luda [366]

Answer:

0.0334N

Explanation:

Given parameters:

M1 = 5 x 10⁶kg

M2 = 1 x 10⁶kg

Distance = 100m

Unknown:

Gravitational force = ?

Solution:

To solve this problem, we use the Newton's law of universal gravitation.

Fg = $\frac{G m1 m2}{r^{2} }$

G is the universal gravitation constant

m is the mass

r is the distance

Fg = $\frac{6.67 x 10^{-11} x 5 x 10^{6} x 1 x 10^{6} }{100^{2} }$ = 0.0334N

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3 years ago

Fermentation is a _________ process.

ivanzaharov [21]

Fermentation is an aerobic process which means it uses oxygen. anaerobic is a process with out oxegyn

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3 years ago

What is the mass of a bullet in free fall with a force of 300N?

Valentin [98]

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3 years ago

When 24500J of energy is supplied to a 2.0 kg block of aluminum.Its temperature rise from 20oc to 35oc.The block is well insulat

True [87]

Explanation:

Amount of heat supplied (Q) = 24500 J

Mass (m) = 2 kg

Initial temperature (t1) = 20 ° C

Final temperature (t2) = 35 ° C

Difference in temperature (dt) = t2 - t1 = ( 35 - 20) °C = 15 ° C

Now Specific heat capacity (S) = ?

We know we have the formula;

Q = m * s * dt

24500 = 2 * s * 15

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S = 24500 / 30

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The specific heat capacity is 816.67 J/kg°C.

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3 years ago

Alice holds a black belt in Taekwondo and her fist has a mass of 0.5 kg. Her fist obtains a velocity of 5 m/s in 0.1 seconds fro

Zarrin [17]

The average force on the fist is 25 N

Explanation:

First of all, we need to calculate the acceleration of the fist, which is equal to the rate of change of its velocity:

$a=\frac{v-u}{t}$

where:

u = 0 is the initial velocity (it starts from rest)

v = 5 m/s is the final velocity

t = 0.1 s is the time elapsed

Substituting,

$a=\frac{5-0}{0.1}=50 m/s^2$

Now we can calculate the average force applied to the fist by using Newton's second law of motion, which states that the net force applied on an object is equal to the product between its mass and its acceleration:

$F=ma$

where here we have:

m = 0.5 kg (mass of the fist)

$a=50 m/s^2$ (acceleration)

And solving for F, we find the force:

$F=(0.5)(50)=25 N$

Learn more about force and acceleration:

brainly.com/question/3820012

#LearnwithBrainly

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3 years ago