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3 years ago

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PLEASE HELP ASAP PPLLEEAASSEE HALPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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how does gravity cause erosion of a rock?

2 answers:

Katena32 [7]3 years ago

6 0

It effect erosion bc it effects the mtns and the land around us and rocks are out in that land so when it is effected by gravity the land around it causes erosion

solmaris [256]3 years ago

4 0

Answer:

Gravity impacts erosion in direct ways like landslides, mudslides and slump. It can also impact erosion in indirect ways, by pulling rain to the Earth and forcing glaciers downhill.

Explanation:

Gravitational erosion describes the movement of soil or rock due to the force of gravity.

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5) What is the net force caused by the moon acting on earth when the moon is 3.86x10^8 m away? The moon has a mass of 7.46x10^23

Dimas [21]

Answers:

5) $1.99(10)^{21} N$

6) $1.37(10)^{18} N$

7) $1.64(10)^{21} N$

8) $4.29(10)^{10} N$ more than Venus force of gravity on Pluto

Explanation:

According to Newton's law of Universal Gravitation, the force $F$ exerted between two bodies of masses $M$ and $m$ and separated by a distance $R$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{Mm}{R^{2}}$ (1)

Where $G=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$ is the Gravitational Constant

This is the equation we will use to solve each question in this problem.

<h3>5) Gravitational force between Earth and Moon</h3>

In this case we have:

$F_{earth-moon}$ is the gravitational force between Earth and Moon

$M=5.97(10)^{24} kg$ is the mass of the Earth

$m=7.46(10)^{23} kg$ is the mass of the Moon

$R=3.86(10)^{8} m$ is the distance between Earth and Moon

Solving:

$F_{earth-moon}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(5.97(10)^{24} kg)(7.46(10)^{23} kg)}{(3.86(10)^{8} m)^{2}}$ (2)

$F_{earth-moon}=1.99(10)^{21} N$ (3)

<h3>6) Gravitational force between Jupiter and Venus</h3>

Assuming for a moment that the planets are perfectly aligned and all are in the same orbital period, we can make a rough estimation of the distance between Jupiter and Venus, knowing the distance of each to the Sun:

distance between Sun and Jupiter - distance between Sun and Venus=distance between Jupiter and Venus= $R_{jupiter-venus}$ (4)

$R_{jupiter-venus}=778.3(10)^{9} m - 108(10)^{9} m=6.703(10)^{11} m$ (5)

Using this value in the Law of Universal Gravitation equation:

$F_{jupiter-venus}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.90(10)^{27} kg)(4.87(10)^{24} kg)}{(6.703(10)^{11} m)^{2}}$ (6)

$F_{jupiter-venus}=1.37(10)^{18} N$ (7)

<h3>7) Gravitational force between Saturn and Mars</h3>

Using the same assumption we made in the prior question:

distance between Sun and Saturn - distance between Sun and Mars=distance between Saturn and Mars= $R_{saturn-mars}$ (8)

$R_{saturn-mars}=1427(10)^{9} m - 227.9(10)^{9} m=227.9(10)^{9} m$ (9)

Using this value in the Law of Universal Gravitation equation:

$F_{saturn-mars}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.989(10)^{30} kg)(6.42(10)^{23} kg)}{(227.9(10)^{9} m)^{2}}$ (10)

$F_{saturn-mars}=1.64(10)^{21} N$ (11)

<h3>8) How much more is earths force of gravity on Pluto than Venus force of gravity on Pluto?</h3>

Firstly, we need to find $F_{earth-pluto}$ and then find $F_{venus-pluto}$ in order to find the difference.

<u>For $F_{earth-pluto}$ :</u>

$M=5.97(10)^{24} kg$ is the mass of the Earth

$m=1.46(10)^{22} kg$ is the mass of Pluto

$R_{earth-pluto}=5.7504(10)^{12} m$ is the distance between Earth and Pluto

$F_{earth-pluto}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(5.97(10)^{24} kg)(1.46(10)^{22} kg)}{(5.7504(10)^{12} m)^{2}}$ (12)

$F_{earth-pluto}=1.759(10)^{11} N$ (13) Force between Earth and Pluto

<u></u>

<u>For $F_{venus-pluto}$ :</u>

$M=4.87(10)^{24} kg$ is the mass of Venus

$m=1.46(10)^{22} kg$ is the mass of Pluto

$R_{venus-pluto}=5.792(10)^{12} m$ is the distance between Venus and Pluto

$F_{venus-pluto}=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(4.87(10)^{24} kg)1.46(10)^{22} kg)}{(5.792(10)^{12} m)^{2}}$ (14)

$F_{venus-pluto}=1.33(10)^{11} N$ (15) Force between Venus and Pluto

Calculating the difference:

$F_{earth-pluto}-F_{venus-pluto}=1.759(10)^{11} N-1.33(10)^{11} N$

Finally:

$F_{earth-pluto}-F_{venus-pluto}=4.29(10)^{10} N$ (16)

Hence:

Earths force of gravity on Pluto is $4.29(10)^{10} N$ than Venus force of gravity on Pluto.

3 0

3 years ago

Find the density of an object that has a mass of 5 kg and a volume of 50 cm3

serg [7]

Density = mass/volume. 5000/50= 100 grams per cubic centimeter. No substance on Earth has anywhere near that density. Tops is about 20 for osmium and gold.

3 0

3 years ago

Read 2 more answers

If you want to go to a community college and transfer to a four-year university, what classes are required to transfer? How many

bagirrra123 [75]

Typically, most four-year institutions will require the following classes to transfer:

2 English composition courses.

1 Speech course.

1 Critical thinking course.

1 Physical science class.

1 Biological science class.

1 Health class.

2 Physical education courses.

Completion of college algebra

That's all I think

3 0

3 years ago

An athlete whose mass is 87.0 kg is performing weight-lifting exercises. Starting from the rest position, he lifts, with constan

expeople1 [14]

Answer: X = 52,314.12 N

Explanation: Let X be the force the feet of the athlete exerts on the floor.

According to newton's third law of motion the floor gives an upward reaction based on the weight of the athlete and the barbell which is known as the normal reaction ( based on the mass of the athlete and the barbell)

Mass of athlete = 87kg, mass of barbell = 600/ hence total normal reaction from the floor = 87* 61.22/ 9.8 *9.8 = 52,200N.

The athlete lifts the barbell from rest thus making it initial velocity u=0, distance covered = S = 0.65m and the time taken = 1.3s

The acceleration of the barbell is gotten by using the equation of constant acceleration motion

S= ut + 1/2at²

But u = 0

S = 1/2at²

0.65 = 1/2 *a (1.3)²

0.65 = 1.69 * a/2

0.65 * 2 = 1.69 * a

a = 0.65 * 2/ 1.69

a = 0.77m/s²

According to newton's second law of motion

Resultant force = mass * acceleration

And resultant force in this case is

X - 52,200 = (87 + 61.22) * 0.77

X - 52,200 = 148.22 * 0.77

X - 52, 200 = 114.132

X = 114.132 + 52,200

X = 52,314.12 N

6 0

3 years ago

What is the mass of 2.5 mol of Ca, which has a molar mass of 40 g/mol?

ipn [44]

Answer:100 g of ca

Explanation:

4 0

3 years ago