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3 years ago

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D) 3. Two objects will attract one another when they have what

1 answer:

Rufina [12.5K]3 years ago

8 0

Answer:

Explanation: NOTHING IN COMMON

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How many position coordinates are required to identify the position of a system undergoing one-dimensional motion? What symbol s

gregori [183]

One-dimensional motion can be plotted through the Cartesian plane which has a coordinates of (x,y). These coordinates are the abscissa and ordinates. Since, there are two coordinates, the answer to the second item is two.

The symbol that can be used to identify systems position is (x,y). Since this is one dimensional motion, it is possible that one of the two coordinates becomes zero.

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3 years ago

A block of mass 9.2kg rests on a slope an angle of 26.9∘ relative to the horizontal. What is the size of the contact force norma

Olegator [25]

Answer:

80.4 N

Explanation:

As the block is at rest on the slope, it means that all the forces acting on it are balanced.

We are only interested in the forces that act on the block along the direction perpendicular to the slope. Along this direction, we have two forces acting on the block:

- The normal reaction N (contact force), upward

- The component of the weight of the block, $mg cos \theta$ , downward, where m is the mass of the block, g is the gravitational acceleration and $\theta$ is the angle of the incline

Since the block is in equilibrium along this direction, the two forces must balance each other, so they must be equal in magnitude:

$N=mg cos \theta$

And by substituting the numbers into the equation, we find the size of the contact force normal to the slope:

$N=(9.2 kg)(9.8 m/s^2)(cos 26.9^{\circ})=80.4 N$

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3 years ago

In the ENGR 10 lab (E391), there are 50 long light bulbs (P=100 W) and 30 regular bulbs (P=60 W). How much energy is consumed li

Alenkinab [10]

Answer:

Total energy saving will be 0.8 KWH

Explanation:

We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW

30 bulbs are of power 60 W

So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW

Total power of 80 bulbs = 1.8+5 = 6.8 KW

Total time = 3 hour

We know that energy $E=power\times time=6.8\times 3=20.4KWH$

Now power of each CFL bulb = 25 W

So power of 80 bulbs = 80×25 = 2000 W = 2 KW

Energy of 80 bulbs = 2×3 = 6 KWH

So total energy saving = 6.8-6 = 0.8 KWH

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4 years ago

If an object starts at rest and moves 60 meters north along a straight line in 2 seconds, what is the average velocity?

Lana71 [14]

Velocity: 30 m/s north

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3 years ago

Read 2 more answers

180 cm3 of hot tea at 97 °C are poured into a very thin paper cup with 20 g of crushed ice at 0 °C. Calculate the final temperat

Zolol [24]

Answer : The final temperature of the mixture is $91.9^oC$

Explanation :

First we have to calculate the mass of water.

Mass = Density × Volume

Density of water = 1.00 g/mL

Mass = 1.00 g/mL × 180 cm³ = 180 g

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of hot water (liquid) = $4.18J/g^oC$

$c_2$ = specific heat of ice (solid)= $2.10J/g^oC$

$m_1$ = mass of hot water = 180 g

$m_2$ = mass of ice = 20 g

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of hot water = $97^oC$

$T_2$ = initial temperature of ice = $0^oC$

Now put all the given values in the above formula, we get

$(180g)\times (4.18J/g^oC)\times (T_f-97)^oC=-(20g)\times 2.10J/g^oC\times (T_f-0)^oC$

$T_f=91.9^oC$

Therefore, the final temperature of the mixture is $91.9^oC$

8 0

3 years ago