Answer: The period of the subsequent simple harmonic motion is 1.004 sec.
Explanation:
The given data is as follows.
Mass of disk (m) = 2.2 kg, radius of the disk (r) = 61.2 cm,
Formula to calculate the moment of inertia around the center of mass is as follows.
=
= 0.412
Also,
Distance between center of mass and axis of rotation (d) = r = 0.612 m
Moment of inertia about the axis of rotation (I)
I =
I =
= 0.339
Now, we will calculate the time period as follows.
T =
T =
T = 1.435 sec
T =
= 1.004 sec
Thus, we can conclude that the period of the subsequent simple harmonic motion is 1.004 sec.