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bija089 [108]
2 years ago
14

Suppose you learn that November is the main termite-fishing season, when chimps spend a large part of their time eating termites

. Predict how the chimp diet might be different in the month of May
Chemistry
1 answer:
Zanzabum2 years ago
4 0
The chimps will have more food because their food is less in November so I’m may there will be more termites because they have been able to reproduce
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Have an infinite number of significant figures
vovikov84 [41]
The answer is: Non-zero
7 0
3 years ago
If the theoretical yield of RX is 56.0 g , what is it’s percent yield ?b
Angelina_Jolie [31]
<span>the theoretical yield which is the expected yield and the actual yield obtained are not always the same. therefore percent yield is calculated which shows how much of the percentage of the theoretical yield is actually obtained.
the theoretical yield = 56.0 g 
actual yield = 47.0 g 
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percent yield = 83.9 %</span>
8 0
3 years ago
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Each chemical element has an atomic number and a mass number. the atomic number refers to the number of ___________________the e
creativ13 [48]
The atomic number tells us the number of protons and electrons.
The atomic mass tells us the weight of the nucleus, which is the amount of protons and neutrons
5 0
3 years ago
Can anyone help me on this please.
exis [7]
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8 0
2 years ago
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Hard water often contains dissolved Ca2+ and Mg2+ ions. One way to soften water is to add phosphates. The phosphate ion forms in
katrin2010 [14]

Answer:

22.4269 grams of sodium phosphate must be added to 1.4 L of this solution to completely eliminate the hard water ions

Explanation:

We will first write the balanced equation for this scenario

3 CaCl2 + 2 Na3PO4 ----> 6 NaCl + Ca3 (PO4)2

3 Mg(NO3)2 + 2 Na3PO4 -----> 6 NaNO3 + Mg3 (PO4)2

The ratio here for both calcium chloride and magnesium nitrate is 3:2

The number of moles of each compound is equal to

0.054 * 1.4 = 0.0756\\0.093* 1.4 = 0.1302

Using the mole ratio of 3:2, convert each to moles of sodium phosphate.

0.0756 mole of CaCl2 is equal to 0.05\\ Na3PO4

0.1302 mole of CaCl2 is equal to 0.0868 Na3PO4

Converting moles of sodium phosphate to grams of sodium phosphate we get

(0.05 +0.0868) * 163.94 g/mol

22.4269 grams of sodium phosphate must be added to 1.4 L of this solution to completely eliminate the hard water ions

8 0
3 years ago
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