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gregori [183]
3 years ago
9

The following reaction is part of the electron transport chain. Complete the reaction and identify which species is reduced. The

abbreviation Q represents coenzyme Q. Use the appropriate abbreviation for the product.
FADH2 + Q →

The reactant that is reduced is: _____
Chemistry
1 answer:
Olegator [25]3 years ago
4 0

Answer:

FADH_2 + Q --> FAD + QH_2

The reactant that is reduced is FADH_2

Explanation:

The complete equation is as below:

FADH_2 + Q --> FAD + QH_2

<em>Recall that oxidation involves the gain of electrons while reduction involves the loss of electrons.</em>

In the above reaction, FADH_2 loses electrons to coenzyme Q and becomes reduced to FAD, hence the oxidizing agent. Coenzyme Q gains electrons and becomes oxidized to QH_2 , hence the reducing agent.

<u>In order words, </u>FADH_2<u> is reduced while coenzyme Q is oxidized.</u>

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The surface temperatures on land vary more over the course of a year than the surface temperatures on the ocean because land has
bogdanovich [222]

Answer:

Lower heat capacity

Explanation:

The heat or thermal capacity is a physical property defined as the amount of heat a material need in order to elevate a unit in its temperature, this means that water increases its temperature more easily than land.

I hope you find this information useful and interesting! Good luck!

7 0
2 years ago
Hurry please need fast
Nina [5.8K]
I think it might be 2 but I could be mistaken sorry if I am
7 0
2 years ago
150 mL of 0.25 mol/L magnesium chloride solution and 150 mL of 0.35 mol/L silver nitrate solution are mixed together. After reac
Murljashka [212]

Answer:

0.175\; \rm mol \cdot L^{-1}.

Explanation:

Magnesium chloride and silver nitrate reacts at a 2:1 ratio:

\rm MgCl_2\, (aq) + 2\, AgNO_3\, (aq) \to Mg(NO_3)_2 \, (aq) + 2\, AgCl\, (s).

In reality, the nitrate ion from silver nitrate did not take part in this reaction at all. Consider the ionic equation for this very reaction:

\begin{aligned}& \rm Mg^{2+} + 2\, Cl^{-} + 2\, Ag^{+} + 2\, {NO_3}^{-} \\&\to  \rm Mg^{2+} + 2\, {NO_3}^{-} + 2\, AgCl\, (s)\end{aligned}.

The precipitate silver chloride \rm AgCl is insoluble in water and barely ionizes. Hence, \rm AgCl\! isn't rewritten as ions.

Net ionic equation:

\begin{aligned}& \rm Ag^{+} + Cl^{-} \to AgCl\, (s)\end{aligned}.

Calculate the initial quantity of nitrate ions in the mixture.

\begin{aligned}n(\text{initial}) &= c(\text{initial}) \cdot V(\text{initial}) \\ &= 0.25\; \rm mol \cdot L^{-1} \times 0.150\; \rm L \\ &= 0.0375\; \rm mol \end{aligned}.

Since nitrate ions \rm {NO_3}^{-} do not take part in any reaction in this mixture, the quantity of this ion would stay the same.

n(\text{final}) = n(\text{initial}) = 0.0375\; \rm mol.

However, the volume of the new solution is twice that of the original nitrate solution. Hence, the concentration of nitrate ions in the new solution would be (1/2) of the concentration in the original solution.

\begin{aligned} c(\text{final}) &= \frac{n(\text{final})}{V(\text{final})} \\ &= \frac{0.0375\; \rm mol}{0.300\; \rm L} = 0.175\; \rm mol \cdot L^{-1}\end{aligned}.

6 0
3 years ago
The radius of a lithium atom is 130 picometers, and the radius of a fluorine atom is 60 picometers. The radius of a lithium ion,
natali 33 [55]

Answer:

A positive ions is always smaller than the corresponding atom.

A negative ion is always larger than the corresponding atom.

Explanation:

The reason for this is that, when a positive ion is formed, a full shell is usually removed with its electrons thereby reducing the size of the electron cloud and decreasing the size of the electron cloud.

A negative ion is formed by addition of more electrons to the electron cloud hence it spreads out. Interelectronic repulsion accounts for the larger size of the negative ion.

3 0
3 years ago
How many chloride ions are in 2.6 moles of CaCl2?
Rama09 [41]

Answer:

31.31× 10²³ number of Cl⁻ are present in 2.6 moles of CaCl₂ .

Explanation:

Given data:

Number of moles of CaCl₂ = 2.6 mol

Number of Cl₂ ions = ?

Solution:

CaCl₂  → Ca²⁺ + 2Cl⁻

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

In one mole of CaCl₂ there are two moles of chloride ions present.

In 2.6 mol:

2.6×2 = 5.2 moles

1 mole Cl⁻ =   6.022 × 10²³ number of Cl⁻ ions

5.2 mol ×  6.022 × 10²³ number of Cl⁻  / 1mol

31.31× 10²³ number of Cl⁻

8 0
2 years ago
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