Answer:
For oxygen: mass % O = (mass of 1 mol of oxygen/mass of 1 mol of CO2) x 100. mass % O = (32.00 g / 44.01 g) x 100. mass % O = 72.71 %
Explanation:
Answer:
the answer is b mitosis in humans
Each 100 cm3 of air, constitutes 78cm3 nitrogen, 21cm3 oxygen and 1cm3 constitutes of other gases like Argon, ozone, carbon dioxide and water vapour in small amounts.
Answer:
Explanation:
The formation of ammonia that occurred by the reaction of nitrogen and ammonia is expressed as:
⇄ 
where;
The reactants are:
Hydrogen and nitrogen
The product is ammonia.
For the reaction, the equilibrium constant can be expressed as:
![K = \dfrac{[product]}{[reactants]}](https://tex.z-dn.net/?f=K%20%3D%20%5Cdfrac%7B%5Bproduct%5D%7D%7B%5Breactants%5D%7D)
![K = \dfrac{[NH_3]^2}{[N_2]^3[H_2]^3}](https://tex.z-dn.net/?f=K%20%3D%20%5Cdfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5E3%5BH_2%5D%5E3%7D)
From the equilibrium constant conditions, the formation of ammonia and its decomposition due to its reversible reaction back to hydrogen and nitrogen are equal. It implies that the rate of the forward reaction is also equal to that of the backward reaction.
Thus, during when equilibrium is obtained;
Hydrogen, Nitrogen, and Ammonia are present.