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OverLord2011 [107]
2 years ago
7

1. how does a waveform change when you increase the frequency?

Physics
1 answer:
antiseptic1488 [7]2 years ago
5 0

Answer:

1.Wave frequency is the number of waves that pass a fixed point in a given amount of time. The SI unit for wave frequency is the hertz (Hz), where 1 hertz equals 1 wave passing a fixed point in 1 second. A higher-frequency wave has more energy than a lower-frequency wave with the same amplitude.

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Look at Concept Simulation 5.2 to review the concepts involved in this question. Two cars are identical, except for the type of
dimulka [17.4K]

Answer:

Tread design on car B would yield a larger coefficient of static friction between the tires and the road

Explanation:

The car model using the coefficient of static friction doesn't work well with tires. A higher coefficient of static friction would require more force to cause a loss of attraction.

The static frictional force helps to keep the unbanked horizontal turn. This means that the frictional force is the centripetal force.

The tread design of car B ensures that the centripetal force is enough to negotiate the turn. On the other hand, the tread design of car A does not provide the necessary centripetal force, hence car A is unable to negotiate the turn.

Therefore, tread design on car B would yield a larger coefficient of static friction between the tires and the road.

7 0
4 years ago
The energy of a photon of light is __________ proportional to its frequency and __________ proportional to its wavelength.
icang [17]

Answer:

D) directly, inversely

Explanation:

The energy of a photon of light is directly proportional to its frequency and inversely proportional to its wavelength.

Frequency is the number of waves that passes through a point per unit of time.

Wavelength is the is the distance between successive crests or troughs on a wave.

 Mathematically, frequency is related to wavelength and velocity using;

             Energy   =  h x f

                      where h is the Planck's constant

                                  f is the frequency

         

                   Since c  = f ∧

where f is the frequency of the wave

           ∧ is the wavelength of the wave

           c is the speed of light

So;

                 f  = c/∧

  Therefore;

                E  = \frac{h c}{wavelength}

From the equation, we see an inverse relationship between E and wavelength and a direct one with frequency.

           

6 0
3 years ago
An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has t
Lena [83]

Explanation:

The De-Broglie wavelength in terms of potential difference is given by:

\lambda=\dfrac{h}{\sqrt{2meV} }

Where,

h is Planck's constant

m is mass of charged particle

V is potential difference

e is the amount of charge

It means that the De-Broglie wavelength is inversely proportional to the mass.

Since, the mass of the proton is more than the mass of the electron. So, the De- Broglie wavelength of the electron is larger than proton.

3 0
3 years ago
A company designed and sells an ultrasonic​ receiver, which detects sounds unable to be heard by the human ear. The receiver can
Kruka [31]

Answer:

the diameter of the outside edge of the receiver is 8\sqrt{18} \ \ \ inches

Explanation:

From the schematic free body diagram illustrating what the question is all about below;

Let represent A to be the vertex where the receiver is being placed

S to be the focus

BP to be equal to r (i.e radius of the outer edge)

BC to be 2 r   (i.e the diameter)

Given that AS = 4 in and AP is 18 in

Let AP be x- axis and AY be y -axis

A=(0,0)

S=(4,0) = (0,0)

So that the equation of the parabolic path of the receiver will be:

y^2 =4 ax  \\ \\ y^2 = 4*4*x \\ \\ y^2 = 16x

B = (AP, BP)

B = (18, r)

B lies  y² = 16 x

r² = 16 x

r² 16 × 18

r = \sqrt{16*18 } \\ \\ r = 4\sqrt{18}

Diameter BC = 2r

2* 4\sqrt{18} \\ \\= 8\sqrt{18 }  \ \ \ inches

6 0
4 years ago
41. City A lies 30 km directly south of city B. A bus, beginning at city A travels 50 km at 37° north of east to reach city C. H
Nana76 [90]

Answer:

B) 40 km West

Explanation:

Let position of B is origin so with respect of City B the position of A is given as

r_A = 30 km south of city B

now Bus starts from City A and travels a distance of 50 km at 37 degree North of East to reach city C

so it is

r_{CA} = 50(cos37\hat i + sin37 \hat j)

r_{CA} = 40\hat i + 30\hat j

now the position of C is given with respect to A

in order to find the position of C with respect to B we can say

r_C = r_{CA} + r_A

r_C = 40\hat i + 30\hat j + (-30 \hat j)

r_C = 40 \hat i

so in order to reach at city B from city C bus has to travel 40 km towards West

7 0
3 years ago
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