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svet-max [94.6K]
4 years ago
8

What are the five related promotional goals?

Physics
1 answer:
monitta4 years ago
3 0
Price, product, promotion, place , and people of your business
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What are the variables of Boyle's law?
vesna_86 [32]

Answer: pressure and volume

Explanation:

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure of the gas provided temperature is kept constant.

Mathematically, Boyle's law can be explained as: PV = k,

where P is pressure

V is volume, and

k is a constant.

So, increase in the pressure of a gas leads to decrease in its volume and vice versa.

3 0
4 years ago
What is the SI unit used to mesasure force
lukranit [14]

Answer:

The si unit to measure force are Pascels or Pa

Hope this helps

Please mark me as Brainliest

6 0
3 years ago
What is the momentum of a 3 kg bowling ball moving at 3 m/s?
Nataly [62]

Explanation:

<h3>p = mv</h3>

  • <em>p</em> denotes momentum
  • <em>m</em> denotes mass
  • <em>v</em> denotes velocity

→ p = 3 kg × 3 m/s

→ <u>p</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>kg</u><u>.</u><u>m</u><u>/</u><u>s</u>

<u>Option</u><u> </u><u>D</u><u> </u><u>is</u><u> </u><u>corre</u><u>ct</u><u>.</u>

5 0
3 years ago
In each cylinder, draw the piston and the gas particles based on the temperature shown.
tangare [24]
I need more information
8 0
3 years ago
"The International Space Station (ISS) orbits at a distance of 350 km above the surface of the Earth. (a) Determine the gravitat
vagabundo [1.1K]

Answer:

(a) g = 8.82158145m/s^2.

(b) 7699.990192m/s.

(c)5484.3301s = 1.5234 hours.(extremely fast).

Explanation:

(a) Strength of gravitational field 'g' by definition is

g = \frac{M_{(earth)} }{r^2} G , here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.

r = 6721,000 meters, putting this value in above equation gives g = 8.82158145m/s^2.

(b) We have to essentially calculate centripetal acceleration that equals new 'g'.

a_{centripetal}=\frac{V^2}{r} =g here g is known, r is known and v is unknown.

plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.

(c)  S = vT,  here T is time period or time required to complete one full revolution.

S =  earth's circumfrence , V is calculated in (B) T is unknown.

solving for unknown gives T = 5484.3301s = 1.5234hours.

3 0
3 years ago
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