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svet-max [94.6K]
4 years ago
8

What are the five related promotional goals?

Physics
1 answer:
monitta4 years ago
3 0
Price, product, promotion, place , and people of your business
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A deer is running from a mountain lion when it encounters a fence that is 1.50 m high. Seeing the fence, the deer jumps, leaving
Novosadov [1.4K]

Answer:

Explanation:

Given

Initial Velocity (u)=13 m/s

angle=29^{\circ}

distance between fence and deer=2.5 m

We consider deer jump similar to projectile motion

equation of trajectory

y=xtan\theta -\frac{gx^2}{2u^2(cos\theta )^2}

y=2.5tan(29)-\frac{9.8\times 2.5^2}{2\times 13^2\times (cos29)^2}

y=1.385-0.2368=1.148 m

Thus deer will cross the fence with an difference in its jump and fence

1.5-1.148=0.351 m

h_{max}=\frac{u^2sin^2\theta }{2g}

h_{max}=\frac{13^2\times (sin29)^2}{2\times 9.8}

h_{max}=2.02 m

so deer rises during when it is over fence

8 0
4 years ago
A tennis ball with a speed of 11.3 m/s is moving perpendicular to a wall. after striking the wall, the ball rebounds in the oppo
Arlecino [84]

To calculate the average acceleration of the ball we use the formula,

a= \frac{v_{f} -v_{i}}{t}

Here, v_{f} is the final velocity of the ball and v_{i} is the initial velocity of the ball t is the time in contact with the wall.

Given v_{i} = 11.3 m/s towards the wall and v_{f} = 7.2207 m/s

away from the wall and t=0.00803 s.

Substituting these values in above formula , we get

a=\frac{(-7.2207 m/s)-11.3 m/s}{0.00803 s}

Herev_{f} is negative because ball is moving away from the wall.

a= - 2306 .4 \ m/s^{2}

Therefore, average acceleration of the ball is - 2306 .4 \ m/s^{2} (away from the wall).

 

4 0
4 years ago
Receiver maxima problem. When the receiver moves through one cycle, how many maxima of the standing wave pattern does the receiv
shusha [124]

Answer:

Two.

Explanation:

  • A standing wave or stationary wave are the type of wave in which it oscillates with time but the amplitude does not move.
  • One complete wave consists of two loops.
  • It means that when the receiver moves through one cycle, two maxima of standing wave pattern the receiver pass through.
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First one is leaves second one is dams
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3b. Grace drives her car with a constant speed
miskamm [114]

Time = (distance covered) / (speed)

Time = (224 mi) / (56 mi/hr)

<em>Time = 4 hours</em>

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