Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
Answer:
y = 2
Step-by-step explanation:
Given
![\sqrt[3]{3y+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3y%2B2%7D)
+ 4 = 6 ( subtract 4 from both sides )
= 2 ( cube both sides )
3y + 2 = 2³ = 8 ( subtract 2 from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
Answer: Independent
Step-by-step explanation: Just multiply the probability of the first event by the second.
Answer:
11 units i think
Step-by-step explanation:
9514 1404 393
Answer:
y-4 = -2(x+1)
Step-by-step explanation:
The point-slope equation of a line is ...
y -k = m(x -h) . . . . . line with slope m through point (h, k)
You have m = -2 and (h, k) = (-1, 4). Putting these numbers into the above form gives ...
y -4 = -2(x +1)
