For this case we have an equation of the form:
f (w) = A * (b) ^ w
Where,
A: initial amount
b: growth rate
w: number of weeks
Substituting values we have:
f (w) = 400 * (1.05) ^ w
Answer:
the beetle population can be determined after a number of weeks, w, with the following function:
f (w) = 400 * (1.05) ^ w
It should say $15.50. Parking = p. n = number of people.
n15.50 + 7 is the equation.
She can bring 6 people, because (6 * 15.50) + 7 = $100
Glad to help!
Answer:
The Possible model is binomial distribution model.
Step-by-step explanation:
The argument that both students cheated in the exam can be proved by a hypothesis that both the students got the same answers incorrectly.
The same incorrect answers prove that both students have cheated on the test.
Therefore the sample of incorrect answers is, n = 8
Thus, the success probability, P = 0.25
Since the given condition has only two outcomes that are choosing the same answer or not choosing the same answer. Thus, this can be solved by the binomial distribution model.
So, binomial distribution with n = 8 and p = 0 .25.
Based on the fact that the snake was placing the mice one - by - one into a jar, this is A. Combining sets.
<h3>What does combining sets entail?</h3>
When sets are combined, it means that numbers from a certain set of variables are combined with those from another set.
The snake had captured the mice separately which means they were in different sets. Putting them into one jar means they are being combined so this is combining sets.
Find out more on number and operations standards at brainly.com/question/20628271.
#SPJ1
Answer:
54
Step-by-step explanation:
To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.
The perimeter of the given triangle = IK + KM + MI
IK = IJ + JK = 13
KM = KL + LM = ?
MI = MN + NI ?
Let's find the length of each tangents.
NI = IJ = 5 (tangents from external point I)
JK = IK - IJ = 13 - 5 = 8
JK = KL = 8 (Tangents from external point K)
LM = MN = 14 (Tangents from external point M)
Thus,
IK = IJ + JK = 5 + 8 = 13
KM = KL + LM = 8 + 14 = 22
MI = MN + NI = 14 + 5 = 19
Perimeter = IK + KM + MI = 13 + 22 + 19 = 54
