<h3>
After 22 days the length of the road is = 75 units.</h3>
Step-by-step explanation:
Given,
L=53 +D L = the length of road and D = number of day
After 22 days the length of the road is = (53+ 22)
= 75 units
Answer:
(a) 
(b) 4 miles
Step-by-step explanation:
Given:
The sequence of run is an arithmetic sequence.
Miles traveled on day 1 = 1 mile
Miles traveled on day 7 = 2 miles
(a).
Explicit formula for an arithmetic sequence is given as:
Here, 
So,
Therefore, the explicit definition of the above sequence is given as:
Where, 
is the miles covered on 
day.
(b)
In order to find the distance covered by her on day 19, we plug in 19 for n in the above formula. This gives,
Therefore, the number of miles covered by her on day 19 is 4 miles.
Answer:
1 2/3 x 9/16
Step-by-step explanation:
Answer:
Yes, result is significant ; PVALUE < α
Step-by-step explanation:
Given :
x = 536
n = sample size = 1012
Phat = x / n = 536 / 1012 = 0.5296 = 0.53
H0 : P0 = 0.5
H1 : P0 > 0.5
Test statistic :
(Phat - P0) ÷ sqrt[(P0(1 - P0)) / n]
1-P0 = 1 - 0.5 = 0.5
(0.53 - 0.5) ÷ sqrt[(0.5*0.5)/1012]
0.03 ÷ 0.0157173
= 1.9087
Pvalue :
Using the Pvalue from test statistic :
Pvalue = 0.02815
To test if result is significant :
α = 0.05
0.02815 < 0.05
Pvalue < α ; Hence, result is significant at α=0.05; Hence, we reject H0.
A^2 +a-6. You use the method of foiling where you multiply the first two terms, the the outside terms, the inside terms, then the last terms. You would do a•a, then a•-2 the a•3 then 3•-2. You would get a^2 -2a +3a -6. Then combine like terms to get your answer.
