1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hichkok12 [17]
3 years ago
13

Match it to its definition please. •PLEASE HELP !! ILL GIVE BRAINLIEST !! 100 POINTS

Mathematics
2 answers:
RideAnS [48]3 years ago
3 0
1. E
2. B
3. D
4. C
5. A Hope this helped!
beks73 [17]3 years ago
3 0

Answer:

1-D

2-E

3-B

4-C

5-A

HOPE IT HELPED U!!

You might be interested in
Delila has 4 coins. If Delila flips all the coins at once, how many outcomes are in the sample space?
Ugo [173]

Answer:0

Step-by-step explanation:

because once you flip all of them there all in the air and there flipped

3 0
3 years ago
Which whole numbers fall between .53 and 2.5
aleksley [76]

There are only <u>2 whole numbers that fall between .53 and 2.5</u>. (<em>Whole numbers are basically numbers we count with through our daily life.</em>)

<u>1 is greater than .53 and 2 is less than 2.5</u>. Your answer is 1 and 2.

5 0
3 years ago
Your starter to find the slope of the line
sergejj [24]
Slope is 3/1 (3 simplified)
4 0
2 years ago
Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
jek_recluse [69]

Answer:

\mathbf{a)} \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\\\mathbf{b)} \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee \; F(x)\\\mathbf{c)} \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)\\\mathbf{d)} \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)\\\mathbf{e)} \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

Step-by-step explanation:

Let X be a set of all students in your class. The set X is the domain. Denote

                                        C(x) -  ' \text{$x $ has a cat}'\\D(x) -  ' \text{$x$ has a dog}'\\F(x) -  ' \text{$x$ has a ferret}'

\mathbf{a)}

Consider the statement '<em>A student in your class has a cat, a dog, and a ferret</em>'. This means that \exists x \in X so that all three statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                         \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)

\mathbf{b)}

Consider the statement '<em>All students in your class have a cat, a dog, or a ferret.' </em>This means that \forall x \in X at least one of the statements C(x), D(x) and F(x) is true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                        \left( \forall x \in X\right) \; C(x) \; \vee \; D(x) \; \vee F(x)

\mathbf{c)}

Consider the statement '<em>Some student in your class has a cat and a ferret, but not a dog.' </em>This means that \exists x \in X so that the statements C(x), F(x) are true and the negation of the statement D(x) . We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

                      \left( \exists x \in X\right) \; C(x) \; \wedge \; F(x) \; \wedge \left(\neg \; D(x) \right)

\mathbf{d)}

Consider the statement '<em>No student in your class has a cat, a dog, and a ferret..' </em>This means that \forall x \in X none of  the statements C(x), D(x) and F(x) are true. We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as a negation of the statement in the part a), as follows

\neg \left( \left( \exists x \in X\right) \; C(x) \; \wedge \; D(x) \; \wedge \; F(x)\right) \iff \left( \forall x \in X\right) \; \neg C(x) \; \vee \; \neg D(x) \; \vee \; \neg F(x)

\mathbf{e)}

Consider the statement '<em> For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.' </em>

This means that for each of the statements C, F and D there is an element from the domain X so that each statement holds true.

We can express that in terms of C(x), D(x) and F(x) using quantifiers, and logical connectives as follows

           \left((\exists x\in X)C(x) \right) \wedge  \left((\exists x\in X) D(x) \right) \wedge \left((\exists x\in X) F(x) \right)

5 0
3 years ago
Andreas drew the model below to represent the equation 20 plus ten equals blank times (4 plus 2) What is the missing value in An
Vadim26 [7]

Answer:5

Step-by-step explanation:

20+10=x(4+2)

30= x(6)

30/6=5

8 0
3 years ago
Read 2 more answers
Other questions:
  • Please help i’m so confused asap!!!!!
    9·1 answer
  • Lee drove 420 miles and used 15 gallons pf gasoline.How many miles did Lee's car travel per gallon of gasoline?
    11·1 answer
  • Christy dove to a depth of 12 feet below the surface of the water. Write the depth as an integer
    7·1 answer
  • Fred works as an
    13·1 answer
  • Can someone please help me on this one!
    15·2 answers
  • The point (-4,4) is a solution for the system contains lines ____and ____
    14·1 answer
  • Write a system of equations to describe the situation below, solve using substitution, and fill
    8·1 answer
  • examine the variety of shapes below if a shape has shading then find the area of the Shaded region ​
    13·1 answer
  • This Stem-and-Leaf Plot shows the number of people who attended a local nine-day carnival.
    6·2 answers
  • I forgot how to do this
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!