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Mademuasel [1]
2 years ago
9

Please answer fast and give expaination I will give brainliest

Mathematics
1 answer:
loris [4]2 years ago
5 0

Answer:

Agree.

Step-by-step explanation:

1. (5^r)^t can be represented simply as 5^rt.

2. when r as negative integer, t as positive integer, rt is always a negative integer

3. when ever the indices rt is negative, the number 5^rt will be less than 1, thus cannot be a whole number for sure.

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Let $ 500 be paid at the end of each quarter for 5 years. If the interest is earned rate of 13%, compounded quarterly, find the
kap26 [50]

Answer:

Future value of annuity (FV) = $13,782.12 (Approx)

Step-by-step explanation:

Given:

Periodic payment p = $500

Interest rate r = 13% = 13%/4 = 0.0325 (Quarterly)

Number of period n = 5 x 4 = 20 quarter

Find:

Future value of annuity (FV)

Computation:

Future\ value\ of\ annuity\ (FV)=p[\frac{(1+r)^n-1}{r} ] \\\\Future\ value\ of\ annuity\ (FV)=500[\frac{(1+0.0325)^{20}-1}{0.0325} ] \\\\Future\ value\ of\ annuity\ (FV)=13,782.1219 \\\\

Future value of annuity (FV) = $13,782.12 (Approx)

7 0
3 years ago
I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

---------------------------------------------------------------------

Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

-------------------------------------------------------------

Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
Solve 11 ≤ w + 3.4 i dont know the answer please help me
shepuryov [24]

Answer:

7.6 ≤w

Step-by-step explanation:

Hey there!

In order to solve this inequality, you need to simplify the inequality like the following:

Subtract 3.4 from both sides

7.6 ≤w

This means that w is greater than or equal to 7.6

6 0
2 years ago
Anyone know what the answer to this is?
MariettaO [177]
It's the 3rd answer

1 \div (36a^{4}{b}^{10} )
8 0
3 years ago
Read 2 more answers
(easy) If ΔEFG ~ ΔLMN with a ratio of 3:1, which of the following is true?
alexandr402 [8]

Answer:

segment EG over segment LN equals segment FG over segment MN

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

In this problem

The corresponding sides are

EF and LM

EG and LN

FG and MN

The corresponding angles are

∠E≅∠L

∠F≅∠M

∠G≅∠N

therefore

EF/LM=EG/LN=FG/MN=3/1

7 0
3 years ago
Read 2 more answers
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