ANSWER: -57
14+{−2+3[1+3(−6−2)]}
= 14+{−2+3[1+3(-8)]}
= 14+{−2+3[1+(-24)]}
= 14+{−2+3[1-24]}
= 14+{−2+3[-23]}
= 14+{−2+[-69]}
= 14+{−2-69}
= 14+(-71)
= 14 - 71
= -57
Given Problem to be solved :
If the day before yesterday was sunday? What day is one week from today.
Let's analyze this given situation:
First the days before yesterday is
=> SUnday
So meaning yesterday is
=> Monday
And today is
=> Tuesday.
Now, what day will be one week from now, we all know that 1 week has 7 days. SO let's start counting:
1. Wednesday
2. Thursday
3. Friday
4. Saturday
5. Friday
6. Sunday
7. Monday.
Thus, the day is MOnday
Answer:
Step-by-step explanation:
so the question lets us know 3 things:
1) Sarah has a 27 ft pipe
2) she cuts 6 ft off
3) she cuts remaining pipe into 7 equal sections
what we don't know from the question is how big each of those 7 sections were. To form the equation we do this.
Since we know Sarah has 27 ft of pipe that would be our answer of the equation.
Sarah also removed 6 ft and the rest of the pipe she cut up into 7 small sections of equal length. since we don't know the length of the 7 smaller sections we will use the variable X to represent the length. this means that 6ft + 7x (X is the length of the pipes, and we multiply by 7 since there are 7 of them) must equal Sarah's total length of 27ft, therefore meaning our education would be
to solve for how long each pipe was, we need to solve for X by rearranging the equation as shown bellow.
Answer:
S(t) = -4.9t^2 + Vot + 282.24
Step-by-step explanation:
Since the rocket is launched from the ground, So = 0 and S(t) = 0
Using s(t)=gt^2+v0t+s0 to get time t
Where g acceleration due to gravity = -4.9m/s^2. and
initial velocity = 39.2 m/a
0 = -4.9t2 + 39.2t
4.9t = 39.2
t = 8s
Substitute t in the model equation
S(t) = -49(8^2) + 3.92(8) + So
Let S(t) =0
0 = - 313.6 + 31.36 + So
So = 282.24m
The equation that can be used to model the height of the rocket after t seconds will be:
S(t) = -4.9t^2 + Vot + 282.24