Heat? I need more details but im sure it is heat.
Answer:
No, he won't be drowned.
Explanation:
We have given,
The height of the student = 5 feet,
Depth of the pool( in feet ) = x ( say ) < 5 feet,
Since, the depth of the pool < height of the student,
Thus, if the student went for swimming in a pool, however he does not know swimming, he will not be drowned until he is suffering from an injury or external force.
From the graph, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
From the question, these are the given parameters;
Part A
The net work done will be the area under the graph.
From position X = 2m to X = 8m gives us the shape of a trapezium.
A = 1/2( a + b )h
A = 1/2( 2 + 6 ) x 8
A = 8 x 4
A = 32 Nm
From X = 0 to X = 2 gives us the shape of a triangle.
A = 1/2bh
A = 1/2 x 2 x (-4)
A = -4 x 1
A = -4 Nm
Net Work done = 32 - 4
Net work done = 28 Nm
Part B
Applying the concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m
Net Work done = 1/2m
Substitute all the necessary parameters
28 = 1/2 x 5.5 x 
5.5
= 56
= 56/5.5
= 10.18
V = 
V = 3.19 m/s
Therefore, net work done on the box and the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively
Learn more about work done here: brainly.com/question/8119756
Answer: 62.86 coulombs
Explanation:
Resistance (R) = 210Ω
Voltage of battery (V) = 110V
total amount of charge (Q) = ?
Time (T) = 2 minutes
The SI unit of time is seconds so convert 2 minutes to seconds
(If 1 minute = 60 seconds
2 minutes = 2 x 60 = 120 seconds)
To get the total charge, first get the current (I) flowing in the circuit by applying the formula V = IR
110V = I x 210Ω
I = 110V/210Ω
I = 0.524 Amps
Then, apply the formula
Charge = current x time
i.e Q = IT
Q = 0.524 Amps x 120 seconds
Q = 62.86 coulombs
Thus, 62.86 coulombs of charge passes through the circuit.
Answer:
True
Explanation:
A coaxial cable is a type of cable that has an inner conductor surrounded by an insulating layer, surrounded by a conductive shielding.