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iVinArrow [24]
2 years ago
13

!!!

Physics
1 answer:
slavikrds [6]2 years ago
5 0

Answer:

0.5

Explanation:

I think it is this beacause if u have the answer you have that

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What is A, B and C?
Dominik [7]
Heat? I need more details but im sure it is heat.
8 0
4 years ago
A 5 feet tall man went for swimming in a pool.He saw the depth of water in the pool less than 5 feet.Will he be drowned? Write w
jenyasd209 [6]

Answer:

No, he won't be drowned.

Explanation:

We have given,

The height of the student = 5 feet,

Depth of the pool( in feet ) = x ( say ) < 5 feet,

Since, the depth of the pool < height of the student,

Thus, if the student went for swimming in a pool, however he does not know swimming, he will not be drowned until he is suffering from an injury or external force.

3 0
4 years ago
Read 2 more answers
A horizontal force is applied to a box with a mass equal to 5.5 kg, The graph shows the net force acting on a box as a function
tangare [24]

From the graph, net work done on the box and  the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively

From the question, these are the given parameters;

  • Mass M = 5.5 Kg
  • Position X = 0 to X = 8m

Part A

The net work done will be the area under the graph.

From position X = 2m to X = 8m gives us the shape of a trapezium.

A = 1/2( a + b )h

A = 1/2( 2 + 6 ) x 8

A = 8 x 4

A = 32 Nm

From X = 0 to X = 2 gives us the shape of a triangle.

A = 1/2bh

A = 1/2 x 2 x (-4)

A = -4 x 1

A = -4 Nm

Net Work done = 32 - 4

Net work done = 28 Nm

Part B

Applying the concepts of work and energy to solve for the speed of the box when it reaches position x = 8.0 m

Net Work done = 1/2mV^{2}

Substitute all the necessary parameters

28 = 1/2 x 5.5 x V^{2}

5.5V^{2} = 56

V^{2} = 56/5.5

V^{2} = 10.18

V = \sqrt{10.1818}

V = 3.19 m/s

Therefore, net work done on the box and  the speed of the box when it reaches position x = 8.0 m are 28 Nm and 3.2 m/s respectively

Learn more about work done here: brainly.com/question/8119756

4 0
3 years ago
A 210Ω resistor is connected in a circuit with a 110V battery. What total amount of charge passes through a point in the circuit
irina1246 [14]

Answer: 62.86 coulombs

Explanation:

Resistance (R) = 210Ω

Voltage of battery (V) = 110V

total amount of charge (Q) = ?

Time (T) = 2 minutes

The SI unit of time is seconds so convert 2 minutes to seconds

(If 1 minute = 60 seconds

2 minutes = 2 x 60 = 120 seconds)

To get the total charge, first get the current (I) flowing in the circuit by applying the formula V = IR

110V = I x 210Ω

I = 110V/210Ω

I = 0.524 Amps

Then, apply the formula

Charge = current x time

i.e Q = IT

Q = 0.524 Amps x 120 seconds

Q = 62.86 coulombs

Thus, 62.86 coulombs of charge passes through the circuit.

6 0
4 years ago
A coaxial cable consists of alternating coaxial cylinders of conducting and insulating material.
olga2289 [7]

Answer:

True

Explanation:

A coaxial cable is a type of cable that has an inner conductor surrounded by an insulating layer, surrounded by a conductive shielding.

4 0
3 years ago
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