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3 years ago

Introduction to Forces Warm-Up Active How do forces affect the motion of an object?

Physics

2 answers:

julia-pushkina [17]3 years ago

5 0

Answer:

Because of my physics teacher I would put this entire explanation below if i were u

Explanation:

Forces affect how objects move. They may cause motion; they may also slow, stop, or change the direction of motion of an object that is already moving.

Since force cause changes in the speed or direction of an object, we can say that forces cause changes in velocity. Remember that acceleration is a change in velocity. So forces cause acceleration.

In-s [12.5K]3 years ago

4 0

Answer:

Forces can affect an object.

Balanced forces allow an object to continue moving at a constant motion (law of inertia).

Unbalanced forces cause a change in motion.

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frosja888 [35]

PART A)

As we know that energy of light depends on its wavelength and frequency as following formula

$E = \frac{hc}{\lambda} = h\nu$

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more

also we know that

$\nu = \frac{c}{\lambda}$

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium

PART B)

Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy

When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.

here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current

So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current

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3 years ago

Read 2 more answers

1.a machine gun fires a ball with an initial velocity of 600m/s with an elevation of 30° with respect to the ground neglecting a

Sedbober [7]

Answer:

See explanation

Explanation:

a) maximum height of a projectile = u sin^2θ/2g

H= 600 × (sin 30)^2/2 × 10

H= 7.5 m

b) Time of flight

t= 2u sinθ/g

t= 2 × 600 sin 30/10

t= 60 seconds

Range

R= u^2sin2θ/g

R= (600)^2 × sin2(30)/10

R= 31.2 m

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3 years ago

I need help on this question!!!

Irina-Kira [14]

2500
--------=3125
0.8

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Answer:1.5

Explanation:

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Answer:

Explanation:

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