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2 years ago

The center-seeking change in velocity of an object moving in a circle is:

Physics

2 answers:

NeTakaya2 years ago

5 0

The center-seeking change in velocity of an object moving in a circle is the centripetal acceleration.

So, by Newton's laws, we know that an object moving with a given velocity will remain in constant motion with a constant velocity until we apply an acceleration.

So we define acceleration as the rate of change of the velocity, also remember that velocity is a vector (has magnitude and direction), so, if there is a change the direction of the velocity, we have an acceleration that causes that.

In circular motion, the velocity vector is always perpendicular to the radius of the circle, and it can only be possible if the velocity direction is changing constantly. This will happen because of something called centripetal acceleration.

This acceleration points radially inwards (to the center of the circle) so is also perpendicular to the velocity of the moving object, and this is what causes the constant change in the direction of the velocity of the moving object.

Just to give an example, if you have a string with a mass on one end, and with your hand, you rotate the mass (from the string), the tension of the string would be the centripetal acceleration.

If you want to learn more about circular motion, you can read:

brainly.com/question/2285236

Helen [10]2 years ago

4 0

Answer:

centripetal acceleration.

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A block with mass 0.5 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.2 m. W

lianna [129]

Answer:

So coefficient of kinetic friction will be equal to 0.4081

Explanation:

We have given mass of the block m = 0.5 kg

The spring is compressed by length x = 0.2 m

Spring constant of the sprig k = 100 N/m

Blocks moves a horizontal distance of s = 1 m

Work done in stretching the spring is equal to $W=\frac{1}{2}kx^2=\frac{1}{2}\times 100\times 0.2^2=2J$

This energy will be equal to kinetic energy of the block

And this kinetic energy must be equal to work done by the frictional force

So $\mu mg\times s=2$

$\mu\times 0.5\times 9.8\times 1=2$

$\mu =0.4081$

So coefficient of kinetic friction will be equal to 0.4081

5 0

3 years ago

carbon dioxide is formed when two oxygen atoms chemically combine with a carbon atom. which term best describes carbon dioxide

Maru [420]

Pretty sure it's compound

5 0

3 years ago

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A bucket of water of mass 14.0 kg is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.260

ruslelena [56]

Answer:

The tension in the rope is 41.38 N.

Explanation:

Given that,

Mass of bucket of water = 14.0 kg

Diameter of cylinder = 0.260 m

Mass of cylinder = 12.1 kg

Distance = 10.7 m

Suppose we need to find that,

What is the tension in the rope while the bucket is falling

We need to calculate the acceleration

Using relation of torque

$\tau=F\times r$

$I\times\alpha=F\times r$

Where, I = moment of inertia

$\alpha$ = angular acceleration

$\dfrac{Mr^2}{2}\times\dfrac{a}{r}=F\times r$

$F=\dfrac{M}{2}a$ ...(I)

Here, F = tension

The force is

$F=m(g-a)$ ...(II)

Where, F = tension

a = acceleration

From equation (I) and (II)

$\dfrac{M}{2}a=m(g-a)$

$a=\dfrac{g}{1+\dfrac{M}{2m}}$

Put the value into the formula

$a=\dfrac{9.8}{1+\dfrac{12.1}{2\times14.0}}$

$a=6.84\ m/s^2$

We need to calculate the tension in the rope

Using equation (I)

$F=\dfrac{M}{2}a$

Put the value into the formula

$F=\dfrac{12.1}{2}\times6.84$

$F=41.38\ N$

Hence, The tension in the rope is 41.38 N.

6 0

2 years ago

How do i solve this step by step

NikAS [45]

Answer:

176.4 meters

Explanation:

The first equation is for average velocity. The other three are the constant acceleration equations you'll need to know.

v = at + v₀

v² = v₀² + 2a(x − x₀)

x = x₀ + v₀ t + ½ at²

x is the final position

x₀ is the initial position

v is the final velocity

v₀ is the initial velocity

t is time

a is acceleration

Notice that the first equation is independent of position.

The second equation is independent of time.

The third equation is independent of final velocity.

So knowing which information you <em>don't</em> have will point you to which equation you should use.

Let's begin:

"Which one would be best to find the distance the object fell from free-fall if it fell for six seconds, assuming if fell in the absence of air resistance and it still hasn't hit the ground? Solve this problem and show all steps of work."

We want to find the distance (change in position). We're given the time (t = 6 s) and we're given the acceleration (free fall without air resistance, so a = -9.8 m/s²).

We aren't given the final velocity, so the equation we should use is the third one:

y = y₀ + v₀ t + ½ at²

Unfortunately, we aren't told the initial velocity, but if we assume that the object starts at rest, then v₀ = 0 m/s. Substituting all values:

y = y₀ + (0 m/s) (6 s) + ½ (-9.8 m/s²) (6 s)²

y − y₀ = -176.4 m

The displacement is -176.4 m. Distance is the magnitude of displacement, so we can say the object fell 176.4 meters.

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3 years ago

Which sample of copper would demonstrate the GREATEST increase in temperature if 500 J of energy were added to the sample?

inn [45]

Answer:

A) 0.5 kg

Explanation:

Q = mCΔT

where Q is energy,

m is mass,

C is specific heat capacity,

and ΔT is temperature change.

Solving for ΔT:

ΔT = Q / (mC)

ΔT is the largest when m is the smallest.

3 0

2 years ago

Read 2 more answers