Answer:
Power, P = 162.53 Watts
Explanation:
Given that,
Mass, m = 200 g = 0.2 kg
Initial speed of the snake, u = 0
Final speed of the snake, v = 32 m/s
Time, t = 0.63 s
Power of an object is given by :
P = 162.53 Watts
So, the power of the rattlesnake is 162.53 Watts. Hence, this is the required solution.
Answer:
124 kPa
Explanation:
The highest pressure in the water is in the bottom of the cylinder. The reason is because all the weight of the water and the gasoline puts some pressure plus the atmospheric air. So, the absolute pressure would be the one exerted by the atmosphere, the gasoline and the water and is calculated as follows:
≈124 kPa
Answer:
Satellites can gather weather data from much higher altitudes than land-based instruments can.
According to Newton's Second Law of Motion, the force is equal to the mass of an object multiplied by its acceleration. When you talk about gravitational force, the acceleration referred to here is the acceleration due to gravity. This is very familiar to us in physics. The acceleration due to gravity on Earth is equal to 9.81 m/s². It actually depends on the location. According to the Universal Law of Gravitation:
F = Gm₁m₂/d²
The force is a factor of the product of two masses and their distance from each other. The G is a constant called the universal gravitational constants. So, gravitational force is actually a relative force exerted by one body to another.
Going back the Second Law of Motion, we can modify the equation to:
F = mg
Since it is mentioned that the gravity on the moon is only 1/6 of the Earth, then the gravity for moon is:
g,moon = 1/6(9.81) = 1.635 m/s²
So, let's compare the weight of the object with a mass of 10 kg. The weight is actually the force due to gravity pulling you towards the center of the body.
Weight on Earth = (10 kg)(9.81 m/s²) = 98.1 N
Weight on Moon = (10 kg)(1.635 m/s²) = 16.35 N
The mass, on the other hand, is not affected by gravity. It is always constant. Therefore, the mass of the object on the moon is the same with its mass on the Earth.
Answer:
Explanation:
Q1 = +2.50 x 10^-5C and Q2 = -2.50 x 10^-5C, r = 0.50m, F=?
Using Coulomb's law:
F = 1/(4πE) x Q1 x Q2/ r^2
Where
k= 1/(4πE) = 9 x 10^9Nm2/C2
Therefore,
F = 9x 10^9 x 2.50 x 10^-5 x2.50 x
10^-5/. ( 0.5)^2
F= 5.625/ 0.25
F= 22.5N approximately
F= 23N.
To find the direction of the force: since Q1 is positive and Q2 is negative, the force along Q1 and Q2 is force of attraction.
Hence To = 23N, attractive. C ans.
Thanks.
