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Lilit [14]
1 year ago
6

the most likely places where stars and planetary systems are forming in the universe are- the most likely places where stars and

planetary systems are forming in the universe are- in nebulae composed of gas and dust. in regions surrounding quasars. in the rarified space between galaxies. in the centers of galaxies.
Physics
1 answer:
igomit [66]1 year ago
8 0

The most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.

Stars are massive, hot, luminous bodies of gas that emit large amounts of radiation and derive their energy from nuclear fusion. A planetary system comprises of a star and all the objects that revolve around it.

Stars are born in nebulae. They are a cluster of gas and dust scattered throughout a galaxy. Gravitational attraction between the gas and dust particles causes turbulence, which gives rise to knots. When these knots acquire sufficient mass, they collapse, and when the reach a certain temperature, nuclear fusion of hydrogen atoms into helium atoms begins. At this point, star has been born.

Planets can be said to be formed as a by-product of star formation, through a process called accretion. Smaller objects stick together through gravity, forming bigger objects. Gravitational pull from the nearby star and the object's own momentum causes the object to revolve round the star. At this point, a planet has been born.

Thus, the most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.

Learn more about planetary systems here:

brainly.com/question/13092561

#SPJ4

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soldi70 [24.7K]
The correct answer is
<span>force per unit charge.

In fact, the electric field strength is defined as the electric force per unit charge experienced by a positive test charge located in the electric field. In formula:
</span>E= \frac{F}{q}
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3 years ago
An electron with kinetic energy 2.9 keV moving along the positive direction of an x axis enters a region in which a uniform elec
Vladimir79 [104]

The electric force on the electron is opposite in direction to the electric field E. E points in the -y direction, so the electric force will point in the +y direction. The magnitude of the electric force is given by:

F = Eq

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We need to set up a magnetic field such that the magnetic force on the electron balances out the electric force. Since the electric force points in the +y direction, we need the magnetic force to point in the -y direction. Using the  reversed right hand rule, the magnetic field must point in the -z direction for this to happen. Since the direction is perpendicular to the +x direction of the electron's velocity, the magnetic force is given by:

F = qvB

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Eq = qvB

Do some algebra to isolate B:

E = vB

B = E/v

Let's solve for the electron's velocity. Its kinetic energy is given by:

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m = 9.1×10⁻³¹kg

Plug in and solve for v:

4.6×10⁻¹⁶ = 0.5(9.1×10⁻³¹)v²

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Given values:

E = 7500V/m

v = 3.2×10⁷m/s

Plug in and solve for B:

B = 7500/3.2×10⁷

B = 0.00023T

B = 0.23mT

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