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fenix001 [56]
3 years ago
15

The gap between electrodes in a spark plug is 0.060 cm. Producing an electric spark in a gasoline-air mixture requires an electr

ic field of 3.0 x 10^6 V/m. What is the magnitude of the minimum potential difference that must be supplied by the ignition circuit to start a car
Physics
1 answer:
Mandarinka [93]3 years ago
8 0

Answer:

The magnitude of minimum potential difference is 1800 V

Explanation:

Given:

Electric field E = 3 \times 10^{6} \frac{V}{m}

Gap between electrodes d = 0.060 \times 10^{-2} m

For finding the minimum potential difference,

  \Delta V = E \times d

  \Delta V = 3 \times 10^{6} \times 0.060 \times 10^{-2}

  \Delta V = 1800 V

Therefore, the magnitude of minimum potential difference is 1800 V

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