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PtichkaEL [24]
4 years ago
9

Name at least three fundamental differences between the harmonic oscillator dynamics and the simple pendulum dynamics

Physics
1 answer:
xenn [34]4 years ago
8 0

Answer: please find the answer in the explanation.

Explanation:

Harmonic can be experienced by any body that repeats itself. The pattern can be sinusoidal, square, tooth etc.

The fundamental differences between the harmonic oscillator dynamics and the simple pendulum dynamics are:

1.) The harmonic oscillator dynamics can be sinusoidal or square wave so far the motion is periodic while the simple pendulum dynamics is always sinusoidal.

2.) In simple pendulum dynamics, the period of oscillation is independent of the amplitude. While the period in harmonic oscillator dynamics depends on the amplitude.

3.) Differential equation is only one method to analyze the simple pendulum dynamics where there are several methods to analyze the harmonic oscillator dynamics.

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Explanation:

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3 years ago
Solving a series circuit, did I do this correctly? ​
nirvana33 [79]
  • The total resistance in the circuit is 16 Ohms.
  • The total current in the circuit is 0.5 Ampere.
  • The current at R_1 is 0.5 Ampere.
  • The current at R_3 is 0.5 Ampere.
  • The voltage drop atR_1 is 4 volts.
  • The voltage drop at R_2 is 2.5  volts.
  • The voltage drop at R_3 is 1.5 volts.
  • The total power consumed by the circuit is 4watts
  • The power consumed at R_1 is 2 watts
  • The power consumed at R_2 is 1.25 watts

Given:

The voltage across the circuit = V = 8 V

The resistors connected are in series:

R_1=8 \Omega, R_2=5\Omega ,R_3=3 \Omega

To find:

The values of from 1 to 10.

Solution

The voltage across the circuit = V = 8 V

  • The total resistance in the circuit  = R_{eq}

R_{eq}=R_1+R_2+R_3\\=8 \Omega +5 \Omega + 3\Omega =16\omega

  • The total current in the circuit = I

V=IR_{eq}\\I=\frac{V}{R_{eq}}=\frac{8 V}{16 \Omega}=0.5 A (Ohm's law)

  • For series combinations, the current in each resistor remains the same.

So, the current in R_1, R_2 \&R_3:

I_1= I_2= I_3=I=0.5 A\\

  • The voltage drop across at R_1 = V_1

The current across  R_1 = I = 0.5 A

V_1=I\times R_1\\\\=0.5A\times 8\Omega = 4 V

  • The voltage drop across at R_2 =V_2

The current across  R_2 = I = 0.5 A

V_2=I\times R_2\\\\=0.5A\times 5\Omega = 2.5 V

  • The voltage drop across at R_3 = V_3

The current across  R_3 = I = 0.5 A

V_3=I\times R_3\\\\=0.5A\times 3\Omega = 1.5 V

  • The total power consumed by circuit:

P= V\times I \\\\= 0.5 A\times 8 V = 4 watt

  • Power consumed at R_1:

P_1=V_1\times I\\\\= 4V\times 0.5A = 2 watt

  • Power consumed at R_2:

P_2=V_2\times I\\\\= 2.5 V\times 0.5A = 1.25 watt

  • Power consumed at R_3:

P_3=V_3\times I= \\\\1.5 V\times 0.5A = 0.75 watt

Learn more about, current, voltage, resistance, and power of the circuit here:

brainly.com/question/11683246?referrer=searchResults

brainly.com/question/1430450?referrer=searchResults

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A if it is one answer and if it’s multiple choice A and D
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Answer:

They show connections because actual life problems help the students understand the topic better!! Hope this helps

Explanation:

Brainliest would be appreciated

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3 years ago
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