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1 year ago

6

9. What could cause scientist to change their mind?

1 answer:

MakcuM [25]1 year ago

6 0

A if it is one answer and if it’s multiple choice A and D

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Solve the following numerical problems

Eddi Din [679]

Answer:

See below

Explanation:

To change C to F°

F = 9/5 C + 32

= 9/5 ( 45) + 32 =<u> 113° F</u>

To change F to C° <= you could use the same equation...or re-earrange to:

C = 5/9 (F-32)

= 5/9 ( 98.6 - 32) = 37° C

Similarly

100 C =<u> 212 ° F</u>

to change C ° to K add 273.15 = <u>373.15 K </u>

5 0

1 year ago

Which statement describes how a covalent molecule would be formed?

NemiM [27]

Either soft or hard but brittle.

7 0

3 years ago

A heat engine has three quarters the thermal efficiency of a carnot engine operating between temperatures of 65Â°C and 435Â°C if

const2013 [10]

Answer:

The value is $P_e = 31275.2 \ W$

Explanation:

From the question we are told that

The efficiency of the carnot engine is $\eta$

The efficiency of a heat engine is $k = \frac{3}{4} * \eta$

The operating temperatures of the carnot engine is $T_1 = 65 ^oC =338 \ K$ to $T_2 = 435 ^oC = 708 \ K$

The rate at which the heat engine absorbs energy is $P = 44.0 kW = 44.0 *10^{3} \ W$

Generally the efficiency of the carnot engine is mathematically represented as

$\eta = [ 1 - \frac{T_1 }{T_2} ]$

=> $\eta = [ \frac{T_2 - T_1}{T_2} ]$

=> $\eta = 0.3856$

Generally the efficiency of the heat engine is

$k = \frac{3}{4} * 0.3856$

=> $k = 0.2892$

Generally the efficiency of the heat engine is also mathematically represented as

$k = \frac{W}{P}$

Here W is the work done which is mathematically represented as

$W = P - P_e$

Here $P_e$ is the heat exhausted

So

$k = \frac{P - P_e}{P}$

=> $0.2892 = \frac{44*10^{3} - P_e}{44*10^{3}}$

=> $P_e = 31275.2 \ W$

8 0

2 years ago

Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.

KIM [24]

Answer:

The velocity is $v = 4.76 \ m/s$

Explanation:

From the question we are told that

The first distance is $d_1 = 4.0 \ km = 4000 \ m$

The first speed is $v_1 = 5.0 \ m/s$

The second distance is $d_2 = 1.0 \ km = 1000 \ m$

The second speed is $v_2 = 4.0 \ m/s$

Generally the time taken for first distance is

$t_1 = \frac{d_1 }{v_1 }$

$t_1 = \frac{4000}{5}$

$t_1 = 800 \ s$

The time taken for second distance is

$t_1 = \frac{d_2 }{v_2 }$

$t_1 = \frac{1000}{4}$

$t_1 = 250 \ s$

The total time is mathematically represented as

$t = t_1 + t_2$

=> $t = 800 + 250$

=> $t = 1050 \ s$

Generally the constant velocity that would let her finish at the same time is mathematically represented as

$v = \frac{d_1 + d_2}{t }$

=> $v = \frac{4000 + 1000}{1050 }$

=> $v = 4.76 \ m/s$

7 0

3 years ago

A system has two possible energy states, E0 and E1 (with E1 > E0). If the difference between these energy states grows (E0 an

Ugo [173]

Answer:

The number of particles in state E0 over the number of particles in state E1 will reduce

Explanation:

E0 represents the ground level state when all the particles have same energy level.

E1 represents excited state in which only a few particle reaches

E0 and E1 get further apart means that the energy difference between the two level increases.

Thus, the number of particles in state E0 over the number of particles in state E1 will reduce.

5 0

2 years ago