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LUCKY_DIMON [66]
2 years ago
13

PLEASE HELP ASAPP!!!!! PLEASE I’LL TRY TO GIVE BRAINLIEST!

Chemistry
1 answer:
luda_lava [24]2 years ago
6 0

Answer:

Cheap energy

Explanation:

Fossil fuels such as coal, oil, and gas are widely available and are much cheaper than other forms of energy (wind, nuclear, etc.) Fossil fuel products are also quite efficient, as the efficieny of fossil fuels is about 50% (which is actually really good), while solar panels for example are only about 15% efficient.

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You are in charge of inflating balloons for a parade. When you inflate the balloons in the morning, It will be 15 degrees Celsiu
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Answer:

so you answer would be B

Explanation:

well what you would do is add 15+25=40  and what they are asking is whay are the degrees in the balloon so you would have B as your answer

hoped i helped have a great weekend

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Please put them in order
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Calcium, boron, neon, sulfur
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Neutrons are found in the nucleus and separate the other particles so that the strong force can hold the nucleus together. Which
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Protons

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3 years ago
Why are Noble gases inert?
sladkih [1.3K]
Correct answer is <span>C. They have a full shell of valence electrons. </span>
3 0
4 years ago
What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon
Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles

\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles

Al_2O_3+3C\rightarrow 2Al+3CO  

According to stoichiometry :

1 mole of Al_2O_3 require 3 moles of C

Thus 0.59 moles of Al_2O_3 will require=\frac{3}{1}\times 0.59=1.77moles  of C

Thus Al_2O_3 is the limiting reagent as it limits the formation of product and C is the excess reagent as it is present in more amount than required.

As 1 mole of Al_2O_3 give = 2 moles of Al

Thus 0.59 moles of Al_2O_3 give =\frac{2}{1}\times 0.59=1.18moles  of Al

Mass of Al=moles\times {\text {Molar mass}}=1.18moles\times 27g/mol=31.8g

Thus 31.8 g of Al will be produced from the given masses of both reactants.

5 0
3 years ago
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