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Vaselesa [24]
2 years ago
10

Standard reduction potentials are 1.455 V for the PbO2(s)/Pb(s) couple, 1.82 V for Co3 (aq)/Co2 (aq), 3.06 V for F2(g)/HF(aq), 1

.07 V for Br2(l)/Br-(aq), and 1.77 V for H2O2(aq)/H2O(l). Under standard-state conditions, arrange the oxidizing agents in order of decreasing strength.
Chemistry
1 answer:
zavuch27 [327]2 years ago
4 0

Answer:

F2(g)/HF(aq)>Co3 (aq)/Co2 (aq)> H2O2(aq)/H2O(l)> PbO2(s)/Pb(s)>Br2(l)/Br-(aq)

Explanation:

The tendency of any specie to function as oxidizing agent is a highly dependent on the reduction potential of the couple. The more positive the value of the reduction potential of the couple, the better it does as an oxidizing agent.

This implies that we could know a good oxidizing agent by looking at their respective reduction potentials. The couple having the greatest (most positive) reduction potential is selected as the best oxidizing agent. If there are a number of couples at having different reduction potentials, the order of oxidizing ability can be obtained by arranging the species in order of decreasing positive reduction potentials just as we have done in the answer above.

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4 0
3 years ago
Give below are the four mixtures. Choose the correct one which can be separated by winnowing. (i) soybean and chickpeas (ii) whe
victus00 [196]

Answer:

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Explanation:

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2 years ago
An aqueous solution of iron(II) iodide has a concentration of 0.215 molal. The percent by mass of iron(II) iodide in the solutio
Basile [38]

Answer:

6.24%

Explanation:

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So, An aqueous solution of iron(II) iodide has a concentration of 0.215 molal.

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mass % of FeI2 = mass of FeI2 x 100 / total mass

= 66.57x 100 / (1000 +66.57)

= 6.24%

                           

8 0
2 years ago
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7 0
3 years ago
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qwelly [4]

Answer:

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Explanation:

8 0
2 years ago
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