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AveGali [126]
3 years ago
14

How many moles of HCl are required to neutralize 20.0 mL of 1.5 M KOH?

Chemistry
1 answer:
777dan777 [17]3 years ago
8 0
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Option D. The water in Glass A is cooler than the water in Glass B; therefore, the particles in Glass A move slower.

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About 277 Kelvin

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Marcos and Helen study the electron configurations of neutral atoms. They draw the
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A student titrated a 25.00-mL sample of a solution containing an unknown weak, diprotic acid (H2A) with N2OH. If the titration r
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<u>Answer:</u> The concentration of weak acid is 3.674\times 10^{-2}M

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To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

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n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2A

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?M\\V_1=25.00mL\\n_2=1\\M_2=0.1036M\\V_2=17.73mL

Putting values in above equation, we get:

2\times M_1\times 25.00=1\times 0.1036\times 17.73\\\\M_1=\frac{1\times 0.1036\times 17.73}{2\times 25.00}=3.674\times 10^{-2}M

Hence, the concentration of weak acid is 3.674\times 10^{-2}M

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