mol of Na2CO3 = 2.36 x 10⁻⁴
<h3>Further explanation</h3>
Given
Mass : 0.025 g of Na2CO3
Required
moles
Solution
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass :
mol = mass : molar mass
mass = mol x molar mass
Input the value :
mol = mass : MW Na2CO3
mol = 0.025 g : 106 g/mol
mol = 2.36 x 10⁻⁴
Answer:
Melting: solid liquid, Freezing: liquid to solid, Evaporation: liquid to gas.
Explanation:
mark me the brainliest
Metals such as iron, zinc, lead, copper, etc., are in the middle of the reactivity series. These are moderately reactive metals and are usually present as sulphides or carbonates. A metal is obtained from its ore by the processes of reduction or by electrolysis.
Whenever it's asking about the formation of a precipitate, you should not consider the solid form in the reactants, only in the products
BaSO4 (s) + Na2CO3 (aq) --- > BaCO3 (s) + Na2SO4 (aq)
so i think barium carbonat is the precipitate
hope this helps
