When molten rock undergoes crystallization above ground, what type of rock results?
2 answers:
You might be interested in
Answer:
Percentage abundance of 121 Sb is = 57.2 %
Percentage abundance of 123 Sb is = 42.8 %
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.
For first isotope, 121 Sb :
% = x %
Mass = 120.9038 u
For second isotope, 123 Sb:
% = 100 - x
Mass = 122.9042 u
Given, Average Mass = 121.7601 u
Thus,
Solving for x, we get that:
x = 57.2 %
<u>Thus, percentage abundance of 121 Sb is = 57.2 % </u>
<u>percentage abundance of 123 Sb is = 100 - 57.2 % = 42.8 %</u>
Answer:
Alternative C would be the correct choice.
Explanation:
- The dual compounds were evaluated on something like a TLC plate through three separate additives in conducting a TLC study of ferrocene versus acetylferrocene.
- The polar as well as nonpolar ferrocene where nonpolar is about 0.63 with the maximum
value, and indeed the polar is somewhere around 0.19 with
- TLC plate (30:1 toluene/ethanol) established with.
The other three choices are not related to the given circumstances. So that option C would be the appropriate choice.