Answer:
10.11 mL
Explanation:
Given that :
Total volume of decolorizer = 500 mL
A common recipe is equal parts 95% ethanol and acetone.
So;
The volume of 95% ethanol in the decolorizer = 500mL/2 = 250 mL
Let represent V(ml) for the 99% of ethanol needed to make 95% of the 250 mL of ethanol;
Therefore:
V(ml) × 0.99 = 250 × 0.95
V(ml) × 0.99 = 237.5
V(ml) = 237.5/0.99
V(ml) = 239.89 mL
Hence; the amount of water to be added to 95% of ethanol = ( 250 - 239.89 )mL = 10.11 mL
A. Fission creates new elements from which electricity can be generated.
Hope this helps!
Answer:
True.
Explanation:
Dissolution changes the properties of molecules or atom.
The question is incomplete, here is the complete question:
Consider the reaction 
Initially, ![[NH_3(g)]=[O_2(g)]](https://tex.z-dn.net/?f=%5BNH_3%28g%29%5D%3D%5BO_2%28g%29%5D)
= 3.60 M; at equilibrium ![[N_2O_4(g)]=0.60M](https://tex.z-dn.net/?f=%5BN_2O_4%28g%29%5D%3D0.60M)
. Calculate the equilibrium concentration for 
<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M
<u>Explanation:</u>
We are given:
Initial concentration of ![[NH_3(g)]](https://tex.z-dn.net/?f=%5BNH_3%28g%29%5D)
= 3.60 M
Initial concentration of ![[O_2(g)]](https://tex.z-dn.net/?f=%5BO_2%28g%29%5D)
= 3.60 M
For the given chemical equation:
Initial: 3.60 3.60
At eqllm: 3.60-4x 3.60-7x 2x 6x
We are given:
Equilibrium concentration of ![[N_2O_4(g)]](https://tex.z-dn.net/?f=%5BN_2O_4%28g%29%5D)
= 0.60 M
Evaluating the value of 'x'
So, equilibrium concentration of 
Hence, the equilibrium concentration of ammonia is 2.8 M
