Answer:
yes
Explanation:
same properties different size
can i have brainliest pls
Answer: Proton will have larger wavelength
Explanation:
(de-Broglie's equation)
h= Planck constant
m= mass of the particle
v= velocity of the particle
As we can see from the de-Broglie's equation , that wavelength is inversely proportional to the product of mass into velocity of the object.
The wavelength of proton will be higher than that fast moving golf ball because mass of proton 
is very small than that of the golf ball (45.93 g). Proton is moving at slow velocity and the golf ball is moving with fast velocity by which value of product of mass into velocity of proton will be lower than the value of product of mass into velocity of the golf ball which will result in larger value of wavelength of the proton.
Our reaction balanced equation at equilibrium N2(g) + 3 H2(g) ↔ 2 NH3(g)
and we have the Kp value at equilibrium = 4.51 X 10^-5
A) 98 atm NH3, 45 atm N2, 55 atm H2
when Kp = [P(NH3)]^2 / [P(N2)] * [P(H2)]^3
= 98^2 / (45 * 55^3) = 1.28 x 10^-3
by comparing the Kp by the Kp at equilibrium(the given value) So,
Kp > Kp equ So the mixture is not equilibrium,
it will shift leftward (to decrease its value) towards the reactants to achieve equilibrium.
B) 57 atm NH3, 143 atm N2, no H2
∴ Kp = [P(NH3)]^2 / [P(N2)]
= 57^2 / 143 = 22.7
∴Kp> Kp equ (the given value)
∴it will shift leftward (to decrease its value) towards reactants to achieve equilibrium.
c) 13 atm NH3, 27 atm N2, 82 atm H2
∴Kp = [P(NH3)]^2 / [P(N2)] * [P(H2)]^3
= 13^2 / (27* 82^3) = 1.14 X 10^-5
∴ Kp< Kp equ (the given value)
∴it will shift rightward (to increase its value) towards porducts to achieve equilibrium.
The ground<span> state of an electron, the energy level it normally occupies, is the state of lowest energy for that electron. ... An electron </span>can become excited<span> if it is given extra energy, such as if it absorbs a photon, or packet of light, or collides with a nearby </span>atom<span> or particle. (I do not take credit for that answer)</span>
