Answer:
The element that is commonly used to reduce iron oxide would be <u>carbon.</u>
Explanation:
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Answer:
0.004548 M is the concentration of B at equilibrium at 500 K.
Explanation:
A(aq) ⇆ 2 B(aq)
Initially 3.00 M
At equilibrium 3.00 -x 2x
Equilibrium constant of the reaction at 500 K =
Concentration of A at 500 K at equilibrium , [A] = (3.00 -x )M
Concentration of B at 500 K at equilibrium,[B]= 2x
An expression of equilibrium constant is given as:
![K_c=\frac{[B]^2}{[A]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BB%5D%5E2%7D%7B%5BA%5D%7D)

On solving for x:
x = 0.002274 M
[B] = 2 x = 2 × 0.002274 M = 0.004548 M
[A] = (3-x) = 3 M - 0.002274 M =2.997726 M
0.004548 M is the concentration of B at equilibrium.
A covalent bond is formed.
Answer:
T = 3206.89 K
Explanation:
Given that,
Number of moles, n = 1.9 moles
Pressure, P = 5 atm
Volume, V = 100 L
We need to find the temperature of the gas. Let the temperature is T. We know that,
PV = nRT
Where
R is gas constant, R = 0.08206 L-atm/mol-K
Put all the values,

So, the temperature of the gas is 3206.89 K.