Question

If I have 1.9 moles of gas held at a pressure of 5 atm and in a container with a volume of 100 liters, what is the temperature of the gas? 3205K

Answer 1

Answer:

T = 3206.89 K

Explanation:

Given that,

Number of moles, n = 1.9 moles

Pressure, P = 5 atm

Volume, V = 100 L

We need to find the temperature of the gas. Let the temperature is T. We know that,

PV = nRT

Where

R is gas constant, R = 0.08206 L-atm/mol-K

Put all the values,

$T=\dfrac{PV}{nR}\\\\T=\dfrac{5\times 100}{1.9\times 0.08206 }\\\\T=3206.89\ K$

So, the temperature of the gas is 3206.89 K.