Answer:
So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.
Explanation:
So, the atomicity of noble gases is 1. Example. ... So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.
could help
Answer:
c) It describes the affinity an atom has for an electron.
Explanation:
C quite literally describes what electronegativity is, you can rule out most others by looking at periodic trends as attached below.
E = hc/(lamda)
The lamda symbol is wavelength, which this site does not have. I can represent it with an "x" instead.
Plancks constant, h = 6.626×10^-32 J·s
Speed of light, c = 3.00×10^8 m/s
The energy must be greater than or equal to 1×10^-18 J
1×10^-18 J ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / x
x ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / (1×10^-18 J)
x ≤ 1.99×10^-7 m or 199 nm
The wavelength of light must be greater than or equal to 199 nm
9 g of hydrogen - 42 g of nitrogen
5 g of hydrogen - x g of nitrogen
The mass of nitrogen in the second sample is 23.33 g.