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jok3333 [9.3K]
2 years ago
15

Formation of water: 2H2 + 1 O2 --> 2H2O

Chemistry
1 answer:
noname [10]2 years ago
7 0

Answer:

2.2 moles H2O

Explanation:

35g O_2 \mbox{ \cdot }\frac{1mol}{32g/mol} \mbox{ \cdot }\frac{2mol H_2O}{1mol O_2}= 2.1875, which rounds to about 2.2

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PLEASE HELP!!!!
shtirl [24]
1) d

2) b because the independent variable is the thing you change/control in an experiment

3) c because the dependent variable is the thing being measured in an experiment

4)hmm it might be d, as c and a are both correct as different sized feeders would make it an unfair test and different types of food would as well

5) c

6) a

7) b obviously because if he activated them at different times then the ones activated last would have an advantage

6 0
4 years ago
Which statement defines reduction potential when considering a pair of half-cell reactions?
torisob [31]
Reduction is the gain of electrons, then potential of reducción is the tendency of a sustance to gain electrons. In this case the sustance is an electrode.

Then the reduction potential refers to the tendency of one electrode to gain electrons and it is measured against a standard electrode which is the electrode of hydorgen.

When you consider the pair of half-cell reactions, the potential of the cell is the reduction potential - oxidation potential.


3 0
3 years ago
Consider the following chemical equilibrium: CaCO3 (s) Cao (s)+cO2 (g) Now write an equation below that shows how to calculate K
True [87]

Answer:

Kc = Kp/(RT)

Explanation:

Let's consider the following chemical equilibrium:

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

Given the pressure equilibrium constant Kp = pCO₂

We can calculate the concentration equilibrium constant (Kc) using the following expression.

Kc = Kp/(RT)^{\Delta n(g)}

where,

R is the ideal gas constant

T is the absolute temperature

Δn(g) = moles of gaseous products - moles of gaseous reactants = 1 - 0 = 1

The expression for this reaction is:

Kc = Kp/(RT)

4 0
3 years ago
What is the concentration of agcl in an aqueous solution that contains 1.2 x 10-3 gram of agcl in 800. grams of the solution? 1.
Vlada [557]
Concentration can be measured in ppm. ppm means parts mer million. In terms of mass , ppm units are mg/kg. 
concentration of AgCl solution is the mass of AgCl solute in mg per 1 kg of solution. 
mass of AgCl present = 1.2 x 10⁻³ kg = 1.2 mg
mass of solution = 800 g = 0.800 kg
the mass of AgCl in 0.800 kg of solution  = 1.2 mg
therefore mass of AgCl in 1 kg of solution = 1.2 mg / 0.800 kg x 1 kg = 1.5 mg
concentration of AgCl is 1.5 mg/kg
since mg/kg = ppm 
concentration of AgCl = 1.5 ppm
answer is 1.5 ppm
3 0
4 years ago
An atom that ______ electrons is called a positive ion. A. has 0 B. has 8 C. loses D. gains
Kitty [74]

Answer:

Gains

Explanation:

It gets more electrons

8 0
3 years ago
Read 2 more answers
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