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3 years ago

6

During the process of electrolysis, liquid water (H2O) chemically changes into hydrogen gas (H2) and oxygen gas (O2). Based on t

he model below, how many
H2 MOLECULES would be produced?

1 answer:

NNADVOKAT [17]3 years ago

5 0

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

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Please match the orbital type with the correct number of orbitals

saul85 [17]

Hi there!

p = e-3
s = f-1
f = i-7
d = g-5

Hope that helps!
Brady

7 0

3 years ago

`You have to be careful about pouring drano down your pipes since it is mainly hydrochloric acid--you can't do it if they are ma

Zanzabum

Answer:

6.67 moles

Explanation:

Given that:-

Moles of hydrogen gas produced = 10.0 moles

According the reaction shown below:-

$2Al + 6HCl\rightarrow 2AlCl_3 +3H_2$

3 moles of hydrogen gas are produced when 2 moles of aluminium undergoes reaction.

Also,

1 mole of hydrogen gas are produced when $\frac{2}{3}$ moles of aluminium undergoes reaction.

So,

10.0 moles of hydrogen gas are produced when $\frac{2}{3}\times 10.0$ moles of aluminium undergoes reaction.

<u>Moles of Al needed = $\frac{2}{3}\times 10.0$ moles = 6.67 moles</u>

6 0

3 years ago

What does combustion mean

frutty [35]

Answer:

combustion is a high-temperature exothermic redox chemical reaction between a fuel and an oxidant, usually atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke.

6 0

2 years ago

Can someone plz explain ionic and covalent bonding plzzzz!!!

Alexeev081 [22]

Answer:

Ionic Bonding: The formation of an Ionic bond is the result of the transfer of one or more electrons from a metal onto a non-metal.

Covalent Bonding: Bonding between non-metals consists of two electrons shared between two atoms.

Explanation:

4 0

3 years ago

Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe

jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

$n=\frac{m}{M_m}$

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

$n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol$

Now we can find the pressure of the gas by using the ideal gas law:

$pV=nRT$

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

$p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm$

8 0

4 years ago