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3 years ago

What describes the change in Gibbs free energy (∆G) of a spontaneous reaction?

Chemistry

1 answer:

alexandr1967 [171]3 years ago

3 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Gibbs Free energy is defined as amount of useful work that can be done in the system. It is equal to the enthalpy of the reaction minus the product of entropy of the reaction and absolute temperature.

Mathematically,

$\Delta G=\Delta H-T\Delta S$

Where,

$\Delta G$ = Gibbs free energy

$\Delta H$ = Enthalpy of the reaction

$\Delta S$ = Entropy of the reaction

T = Absolute temperature

Sign Convention for Gibbs Free energy:

If $\Delta G$ , it is considered as a Spontaneous reaction.

If $\Delta G>0$ , it is considered as a Non-Spontaneous reaction.

If $\Delta G=0$ , reaction is in equilibrium.

Hence, the correct answer is Option A.

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3 years ago

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3 years ago

At 218°C, Keq=1.2 x 10^-4 for the equilibrium NH4SH(s) ⇋ NH3(g) + H2S(g). Calculate the equilibrium concentrations of NH3 and H2

maksim [4K]

At 218 °C, solid NH₄SH decomposes to form 0.011 M NH₃ and H₂S, as given by its equilibrium constant.

<h3>What is the equilibrium constant?</h3>

The equilibrium constant (Keq) is the ratio of the product of the concentrations of the products to the product of the concentrations of the reactants, all raised to their stoichiometric coefficients.

Only gases and aqueous species are included.

Step 1. Make an ICE chart.

NH₄SH(s) ⇋ NH₃(g) + H₂S(g)

I 0 0

C +x +x

E x x

Step 2. Write the equilibrium constant.

Keq = 1.2 × 10⁻⁴ = [NH₃] [H₂S] = x²

x = 0.011 M

At 218 °C, solid NH₄SH decomposes to form 0.011 M NH₃ and H₂S, as given by its equilibrium constant.

Learn more about equilibrium here: brainly.com/question/5081082

#SPJ1

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2 years ago

Consider the reaction.

Alex_Xolod [135]

Note the signs of equilibrium:-

Reaction don't procede forward or backward
Concentration of products and reactants remains same .

Concentration of A is 2M then concentration of B should be same .

So equilibrium constant K is 1

$\\ \rm\rightarrowtail K=\dfrac{[Products]^a}{[Reactants]^b}$

[B]=[A]^2
[B]=2^2
[B]=4M

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2 years ago