Percentage yield = (actual yield / theoretical
yield) x 100%<span>
The balanced equation for the reaction is,
CH₄(g) + Cl₂<span>(g) </span>→ CH₃Cl(g)
+ HCl(g)</span><span>
Since there is excess of Cl₂ gas, we can assume that all of CH₄ gas are reacted.</span><span>
Moles of CH₄(g) = mass / molar mass</span><span>
= 25.0 g / 16 g/mol
= 1.5625 mol
The stoichiometric ratio between CH₄(g) and CH₃Cl(g)
is 1 : 1</span><span>
Hence moles of CH₃Cl(g) = 1.5625 mol</span><span>
Molar mass of CH₃Cl(g) = 50.5 g/mol</span><span>
Mass of CH₃Cl(g) = number of moles x molar mass</span><span>
= 1.5625 mol x 50.5 g/mol
<span>
= 78.9 g</span>
Hence theoretical yield = 78.9 g
Actual yield = 45.0 g
Hence,
<span> Percentage yield = (45.0 g / 78.9 g) x 100% </span>
<span>
= 57.03%</span></span>
Answer:
the mirror is 12 cm away from the image
Explanation:
; the image will be virtual and it will form at 12 cm distance behind the mirror.
Answer:
The answer is B
Explanation:
Because conduction of heat or electricity occurs through a medium(for eg. The heat from a fire going through a metal pot . So in this example the pot is the medium of conduction).
And in this question the medium of heat conduction is the ground, with the heat moving in an upward motion .
This is a strong base / week acid reaction.
NaOH + CH3COOH
The equilibrium of this reaction is very displaced to the right leading to the formation of the products
Na CH3COO + H2O
Na CH3COOH is a ionic compound which in solutionn will be as Na (+) and CH3COOH(-)
=> CH3COOH + NaOH = CH3 COO(-) + Na(+) + H2O
So, the predominant species in the solution are the ions Na(+) and CH3COO(-).
In general, in an strong base / weak acid titration, the predominant species present at the stoichiometric point will be the cation of the strong base (Na+ in this case) and the conjugate base of the weak acid (the anion of the weak acid, which is CH3COO- in this case).
The answer is predominantly Na(+) and CH3COO(-); predominantly because it is an equlibrium which means that the rectants will also br present.