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Digiron [165]
3 years ago
14

A/1 * B/C =D, You find yourself with 17 guilders (a gold coin) but you are planning on taking a trip to a country where the loca

l currency is the florin. The current exchange rate is 2 guilders for every 3 florins. Using the above exchange rate, and the template for conversions, set up an equation to convert your 17 guilders into florins. What should you place in space B of the template? (Hints: Treat the exchange rate as a conversion factor. Assume no service charge for the transaction) A. 25.5 florins B. 3 florins C. 2 guilders D. 17 guilders
Chemistry
2 answers:
Gemiola [76]3 years ago
6 0

Exchange rate is 2 guilders for every 3 florins

The conversion factor will be

2 guilders / 3 florins = 3 florins / 2 guilders = 1

so if we wish to convert 17 guilders to florins we will use following conversion factor

3 florins / 2 guilders = B / C

D = 17guilders X 3 florins / 2 guilders = 25.5 florins

joja [24]3 years ago
3 0

Answer:

the answer is 3 florins. ur welcome peps

Explanation:

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4. DBearded waste of Co-60 must be stored until it is no longer radioactive. Cobalt-60
Bingel [31]

464 g radioisotope was present when the sample was put in storage

<h3>Further explanation</h3>

Given

Sample waste of Co-60 = 14.5 g

26.5 years in storage

Required

Initial sample

Solution

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

Half-life of Co-60 = 5.3 years

Input the value :

\tt 14.5=No.\dfrac{1}{2}^{26.5/5.3}\\\\14.5=No.\dfrac{1}{2}^5\\\\No=\boxed{\bold{464~g}}

8 0
3 years ago
The enthalpy change for converting 1.00 mol of ice at -50.0 ∘c to water at 60.0∘c is ________ kj. the specific heats of ice, wat
guajiro [1.7K]
First, we have to get:

1- The heat required to increase T of ice from -50 to 0 °C:

according to q formula:

q1 = m*C*ΔT

when m is the mass of ice = mol * molar mass

                                             =  1 mol * 18 mol/g

                                            = 18 g

and C is the specific heat capacity of ice = 2.09 J/g-K

and ΔT change in temperature = 0- (-50) = 50°C

by substitution:

∴q1 = 18 g * 2.09 J/g-K *50°C

       = 1881 J = 1.881 KJ

2- the heat required to melt this mass of ice is :

q2 = n*ΔHfus 

when n is the number of moles of ice = 1 mol

and ΔHfus = 6.01 KJ/mol

by substitution:

q2 = 1 mol * 6.01 KJ/mol

     = 6.01 KJ

3- the heat required to increase the water temperature from 0°C to 60 °C is:

q3 = m*C*ΔT

when m is the mass of water = 18 g 

C is the specific heat capacity of water = 4.18 J/g-K

ΔT is the change of Temperature of water = 60°C - 0°C = 60°C

by substitution:

∴q3 = 18 g * 4.18 J/g-K * 60°C

      = 4514 J = 4.514 KJ

∴the total change of enthalpy = q1+q2+q3

                                                  = 1.881 KJ  +6.01 KJ + 4.514 KJ

                                                  = 12.405 KJ


5 0
3 years ago
What is the quickest way to change liquid to gas
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Heat.   When heat is appplied to liquid it turns into gas.
6 0
3 years ago
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Alik [6]
Mình nghĩ C là đáp án đúng
5 0
3 years ago
What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?
vova2212 [387]
The volume of SO2 produced at 325k   is calculated as  below

calculate  the moles of SO2 produced  which  is calculated as follows

write the  reacting equation
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find the   moles  of  HCl  used
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by  use of mole ratio between  HCl to  SO2  which is  2:1 the moles of SO2 is therefore = 0.411 /2 =0.206  moles  of SO2

use the idea  gas  equation  to calculate the volume SO2
that is V=nRT/P  
where  n=0.206  moles
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V=(0.206 moles x  0.082 L.atm/mol.k x325 k)/1.35 atm = 4.07 L of SO2

3 0
3 years ago
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