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Digiron [165]
3 years ago
14

A/1 * B/C =D, You find yourself with 17 guilders (a gold coin) but you are planning on taking a trip to a country where the loca

l currency is the florin. The current exchange rate is 2 guilders for every 3 florins. Using the above exchange rate, and the template for conversions, set up an equation to convert your 17 guilders into florins. What should you place in space B of the template? (Hints: Treat the exchange rate as a conversion factor. Assume no service charge for the transaction) A. 25.5 florins B. 3 florins C. 2 guilders D. 17 guilders
Chemistry
2 answers:
Gemiola [76]3 years ago
6 0

Exchange rate is 2 guilders for every 3 florins

The conversion factor will be

2 guilders / 3 florins = 3 florins / 2 guilders = 1

so if we wish to convert 17 guilders to florins we will use following conversion factor

3 florins / 2 guilders = B / C

D = 17guilders X 3 florins / 2 guilders = 25.5 florins

joja [24]3 years ago
3 0

Answer:

the answer is 3 florins. ur welcome peps

Explanation:

You might be interested in
What is bohr's model?​
egoroff_w [7]

Answer:

In atomic physics, the Bohr model or Rutherford–Bohr model, presented by Niels Bohr and Ernest Rutherford in 1913, is a system consisting of a small, dense nucleus surrounded by orbiting electrons—similar to the structure of the Solar System, but with attraction provided by electrostatic forces in place of gravity.

4 0
2 years ago
if a lead can be extrated with 92.5% efficiency,what is the mass of ore required to make a lead sphere with 750%cm radius
Lady_Fox [76]
The mass of ore required is 21 700 t.

r = 750 cm

V = \frac{4}{3}  \pi  r^{3} = \frac{4}{3}  \pi  (750 cm)^{3} = 1.767 × 10⁹ cm³

The density of lead is 11.34 g/cm³.

So mass of lead sphere = 1.767 × 10⁹ cm³ × \frac{11.34 g}{1 cm^{3} } = 2.004 ×10¹⁰ g

2.004 ×10¹⁰ g × \frac{1 kg}{1000 g} = 2.004 × 10⁷ kg

2.004 × 10⁷ kg × \frac{1 t}{1000 kg} = 2.004 × 10⁴ t

92.5% efficiency means 92.5 t Pb per 100 t of ore.

Mass of ore = 2.004 × 10⁴ t Pb ×\frac{100 tore}{92.5 t Pb} = 2.17 × 10⁴ t ore = 21 700 t ore

6 0
3 years ago
If a student made a 2.5 solution using 1.5 moles of sucrose how many liters of water were used?
saul85 [17]

Answer:

1 mole.

Explanation:

Hello there!

2.5-1.5=1

Subtract the sucrose moles from the total moles, and there you are!

:)

3 0
3 years ago
It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2
Lapatulllka [165]

Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

n_{HCl}=2*n_{Mg(OH)_2}

And in terms of volumes and concentrations we verify:

V_{HCl}M_{HCl}=2*V_{Mg(OH)_2}M_{Mg(OH)_2}

So we use the given data to proof it:

4.3mL*0.417M=2*11.9mL*0.151M\\1.793=3.594

Therefore, we can conclude the data is wrong by means of the 2:1 mole ratio that for sure was not taken into account. This is also supported by the fact that normalities are actually the same, but the nomality of magnesium hydroxide is the half of the hydrochloric acid normality since the acid is monoprotic and the base has two hydroxyl ions.

Best regards.

4 0
3 years ago
According to the Brensted-Lowry model write the equation for provided acid showing
Taya2010 [7]

Answer:

i dont know sorry

Explanation:

3 0
3 years ago
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