117 L. You can start by making a table to organize the information you are given. Then, you can use the formula PV/T=PV/T and plug in the numbers you have. You then solve for the missing volume. Remember that the initial pressure, temperature, and volume should be on one side of the equal sign, and the final pressure, volume, and temperature should be on the other side.
Answer:
Name Strontium
Atomic Mass 87.62 atomic mass units
Number of Protons 38
Number of Neutrons 50
Number of Electrons 38
Answer:
Explanation:
1 mol of methane = 6.02 * 10^23 molecules
6.70 mol of methane = x
Cross multiply
x = 6.70 * 6.02 * 10^23
x = 4.033 * 10^23 molecules.
The answer to the question is a.
Answer:
1. 3.02 liters
2. 302.2 liters
3. 2.83 grams
Explanation:
Question 1.
Let's convert the molarity in mass.
Molarity is mol/L, so if we convert the moles to mass, we are talking about a mass, in 1L of solution. (mol . molar mass)
0.5 mol . 110.98 g/m = 55.49 g
Now we can make a rule of three:
If 55.49 grams of chloride are in 1L of solution
then 167.5 g of chloride are in (167.5g . 1L) / 55.49 g = 3.02L
For question 2 and 3, we assume STP, where pressure is 1 atm and T° is 273K. - Standard conditions of temperature and pressure (STP)
Let's apply the Ideal gases law equation
P . V = n . R .T
1 atm . V = 13.5 moles . 0.082 l.atm / mol .K . 273K
V = (13.5 moles . 0.082 l.atm / mol .K . 273K) / 1 atm = 302.2 liters (question 2)
Question 3.
1 atm . 31.7 L = n . 0.082 l.atm / mol.K . 273K
(1 atm . 31.7 L ) / (0.082 l.atm / mol.K . 273K) = 1.41 moles → n
Let's convert moles to mass ( mol . molar mass)
1.41 mol . 2g/mol = 2.83 grams