Answer: False
Explanation:
Since the given equation is not balanced properly.
Since oxygen and hydrogen atoms are not balanced.
There should be 6 H2O (g) molecules and 14 mol H2 (g)
Answer: A thing that died a long time ago, and it's bones were preserved in the ground.
Explanation:
Because yes
Answer : The concentration of A after 80 min is, 0.100 M
Explanation :
Half-life = 20 min
First we have to calculate the rate constant, we use the formula :



Expression for rate law for first order kinetics is given by:

where,
k = rate constant = 
t = time passed by the sample = 80 min
a = initial amount of the reactant = 1.6 M
a - x = amount left after decay process = ?
Now put all the given values in above equation, we get


Therefore, the concentration of A after 80 min is, 0.100 M
Answer:
Inversely
Explanation:
pV = k
When p increases, V must decrease for k to remain constant.
When V increases, p must decrease for k to remain constant.
When the product of two variables is a constant, they are inversely proportional to each other.