the answer is : 4.6 M HCL
Answer: RbI (aq) and Zn(CN)2 precipitate
Explanation: zinc cyanide is insoluble in water.
The combustion of an organic compound is mostly written as,
CaHbOc + O2 --> CO2 + H2O
where a, b, and c are supposed to be the subscripts of the elements C, H, and O in the compound. Determining the number of moles of C and H in the product which is the same as that in the compound,
(Carbon, C) : (561 mg) x (12/44) = 153 mg x (1 mmole/12 mg) = 12.75
(Hydrogen, H) : (306 mg) x (2/18) = 34 mg x (1 mmole/1 mg) = 34
Calculating for amount of O in the sample,
(oxygen, O) = 255 - 153 mg - 34 mg = 68 mg x (1mmole/16 mg) = 4.25
The empirical formula is therefore,
C(51/4)H34O17/4
C3H8O1
The molar mass of the empirical formula is 60. Therefore, the molecular formula of the compound is,
C9H24O3
Answer:
Metal name (charge in roman numerals) Non metal
for example Iron (III) chloride
Explanation:
The rule for naming special transition metal are as follows -
a) First name the transition metal
b) Now write the name of the non metal in the chemical formula.
c) Write the charge for the non metal.
d) If there is a polyatomic ion, write the Common Ion Table ,its formula and charge.
e) Based on the total charge on the non-metal or polyatomic ion, deduce the total charge on the transition metal
f) Write the charge of transition metal after the name of metal in Roman Numeral in parentheses
