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serg [7]
2 years ago
6

Which type of bond does this molecule show?

Chemistry
1 answer:
Gekata [30.6K]2 years ago
5 0
The correct answer is D. magnetic bond
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Any five uses of solution.....​
laiz [17]

Answer:

The majority of chemical processes are reactions that occur in solution. Important industrial processes often utilize solution chemistry. "Life" is the sum of a series of complex processes occurring in solution. Air, tap water, tincture of iodine, beverages, and household ammonia are common examples of solutions.Turpentine as a solvent are used in the production of paints, inks and dyes. ↔Water as a solvent is used in the making of food, textiles, soaps and detergents. ↔Alloys are solid solutions that are used in the manufacture of cars, aerospace and other vehicles.Household cleaners like bleach are solutions, they help us to make our houses clean. Beverages such as fizzy drinks, mineral water and tea are solutions. In hydroponics, the roots of plants are immersed in solutions containing dissolved mineral salts.

3 0
3 years ago
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with strong heating calcium carbonate undergoes thermal decomposition how many mole of CaCO3 are there in 50g of calcium carbona
aev [14]
Ca=40
C=12
O=16
1 mole of CaCO3 has 100 grams
So 50 grams is 0.5 mole
6 0
2 years ago
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Arrange the elements in decreasing order of first ionization energy.
just olya [345]

Answer:

The decreasing order of first ionization energy: Se > Ge > In > Cs

The decreasing order of first ionization energy: x > y > z

Explanation:

Ionization energy refers to the energy needed to completely pull out an electron from the valence shell of a neutral gaseous atom.

First ionization energy is the energy involved in the removal of first valence electron.

<u><em>In the periodic table, down the group, as atomic radius of elements increases, the ionization energy decreases </em></u>

<u><em>Whereas, across a period, as atomic radius of elements decreases, the ionization energy increases.</em></u>

PART (A):

Position of the given elements in the periodic table:

Indium (In): Group 13, period 5

Germanium (Ge): Group 14, period 4

Selenium (Se): Group 16, period 4

Caesium (Cs): Group 1, period 6

Thus, the increasing order of atomic radius: Se < Ge < In < Cs

<u>Therefore, the decreasing order of first ionization energy: </u><u>Se > Ge > In > Cs</u>

PART (B):

Given elements:

element x: radius = 110 pm

element y: radius = 199 pm

element z: radius = 257 pm

Thus, the increasing order of atomic radius: x < y < z

<u>Therefore, the decreasing order of first ionization energy:</u><u> x > y > z</u>

5 0
3 years ago
How many molecules of Mg3N2 (magnesium nitride) are formed when excess Mg (magnesium)
dybincka [34]

Explanation:

<em>3Mg(s) + N2(g) = Mg3N2(s)</em>

First check that the equation is balanced. In this case, it is.

Assuming that magnesium is the limiting reactant:

  1. First find the molecular weight using the Periodic Table.

       We find that the atomic mass of magnesium is approximately

       <em>24.3g</em>, so the molecular weight is just <em>24.3g\mol</em>

   

    2. Next we need the mole to mole ratio. As there are <em>3</em>

        magnesiums for <em>1</em> magnesium nitride (shown by the coefficients), the                    

        mole to mole ratio is<em> 1 mol Mg3N2\3 mol Mg.</em>

   

    3. We need the amount of the substance, in grams. Since you have not    

        stated it in the question, I'll just do <em>10g</em> AS AN EXAMPLE. Note that    

       depending on the amount, the LIMITING REAGENT MAY DIFFER.

   4.  Finally, we need the molecular weight of <em>Mg3N2</em>, which we can easily    

        calculate to be around <em>100.9\mol.</em>

<em />

   5.  Putting this all together, we have<em> 10gMg⋅ (mol Mg\24.3gMg) </em>

<em>         (1mol Mg3N2\ 3mol Mg) (100.9g Mg3N2\mol Mg3N2)</em>

     

        the units will cancel to leave <em>gMg3N2</em> (grams of magnesium nitride):

       

<em>        10gMg ⋅ (mol Mg\24.3gMg) (1mol Mg3N2\3mol Mg)</em>

<em>        (100.9g Mg3N2\mol Mg3N2)</em>

<em />

Doing the calculation yields approximately 13.84g.

Assuming that nitrogen is the limiting reactant:

Similarly, following the above steps but with <em>10g</em> of nitrogen yields <em>36.04g</em>

In conclusion, as we produce less amount of <em>Mg3N2</em> when we assumed that <em>Mg</em> was the limiting reagent, magnesium is the limiting reagent and nitrogen is the excess.

Note: This is in THIS CASE, where we have <em>10g</em> of both. The answer may vary depending on the amount of each substance.

7 0
2 years ago
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Which of the following Group 1A elements is the most reactive?
Alisiya [41]
A. Cesium because reactivity of alkali metals increases from the top to the bottom of the group.
7 0
3 years ago
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