Answer:
let us use the expression v = ./2gS in both the cases.
a) In the first case g = 9.8 m/s^2 and S = 10.3 m.
So v = 14.21 m/s
b) in the second case, g = 1.64 m/s^2 and S = 4.2 m = 3.71 m/s
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Explanation:
Missing part of the text:
"Two masses, m1 = 2.12 kg and m2 = 9.01 kg are on a horizontal frictionless surface and they are connected together with a rope as shown in the figure."
and missing figure (see attachment)
Solution:
We can write Newton's second law for the whole system m1-m2 and for m2 only (2 equations). Only one force (F) acts on the m1-m2 system, while if we consider m2 only we have two forces acting on it: F and T (tension), in the opposite direction. So, the two equations are
where a is the acceleration of the system.
From the first equation we get
and substituting it inside the second equation, we get
re-arranging, we get
Using
,
, and using the maximum value of T that is allowed not to break the rope (T=55 N), we can find the maximum allowed value for F:
Answer: The statements are missing hence I will give you a summary of what the big bang theory .
answer : The big bang theory explains how the energies of every speck of the universe came together at a point ( very dense point ) and eventually exploded creating the various galaxies we have today
Explanation:
The Big bang theory describes how the Universe and the various galaxies that exist began some billion of years ago, It describes how the energies of every speck of the universe came together at a point ( very dense point ) and eventually exploded creating the various galaxies we have today
Answer:
The force when θ = 33° is 1.7625 times of the force when θ = 18°
Explanation:
The force on a moving charge through a magnetic field is given by
F = qvB sin θ
q = charge of the moving particle
v = Velocity of the moving charge
B = Magnetic field strength
θ = angle between the magnetic field and the velocity (direction of the motion) of the moving charge
Because qvB are all constant, we can call the expression K.
F = K sinθ
when θ = 18°,
F = K sin 18° = 0.309K
when θ = 33°, let the force be F₁
F₁ = K sin 33° = 0.5446K
(F₁/F) = (0.5446K/0.309K) = 1.7625
F₁ = 1.7625 F
Hope this Helps!!!