Answer:
Period of motion is approximately 0.5447 seconds
Explanation:
We start by calculating the constant "k" of the spring which can be derived from the fact that an object of mass 12 g produced a stretch of 3.4 cm: (we write everything in SI units)
F = k * x
0.012 kg * 9.8 m/s^2 = k 0.034 m
k = 0.012 kg * 9.8 m/s^2 / (0.034 m)
k = 3.46 N/m
now we use the formula for the period (T) of a spring of constant k with a hanging mass 'm':

which in our case becomes:

The acceleration of the car,

Here, v is final velocity, u is initial velocity and t is time taken by the car.
Given
,
and 
Therefore, from above equation
.
Here, negative sign shows deceleration of a car.
Thus the the magnitude of car acceleration is
.
Energy transformation or conversion
Answer:
v = 100 m/s
Explanation:
Given:
v₀ = 0 m/s
a = 10 m/s²
t = 10 s
Find: v
v = at + v₀
v = (10 m/s²) (10 s) + 0 m/s
v = 100 m/s