If you doubled the load resistor in a Wheatstone bridge, the load current would not be half as much. Why not?
1 answer:
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Answer: 313920
Explanation:First, we’re going to assume that the top of the circular plate surface is 2 meters under the water. Next, we will set up the axis system so that the origin of the axis system is at the center of the plate.
Finally, we will again split up the plate into n horizontal strips each of width Δy and we’ll choose a point y∗ from each strip. Attached to this is a sketch of the set up.
The water’s surface is shown at the top of the sketch. Below the water’s surface is the circular plate and a standard xy-axis system is superimposed on the circle with the center of the circle at the origin of the axis system. It is shown that the distance from the water’s surface and the top of the plate is 6 meters and the distance from the water’s surface to the x-axis (and hence the center of the plate) is 8 meters.
The depth below the water surface of each strip is,
di = 8 − yi
and that in turn gives us the pressure on the strip,
Pi =ρgdi = 9810 (8−yi)
The area of each strip is,
Ai = 2√4− (yi) 2Δy
The hydrostatic force on each strip is,
Fi = Pi Ai=9810 (8−yi) (2) √4−(yi)² Δy
The total force on the plate is found on the attached image.
Answer:
The velocity is
Henrietta is at distance from the under the window
Explanation:
From the question we are told that
The speed of Henrietta is
The height of the window from the ground is
Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is
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Generally the time taken for the lunch to reach Henrietta is mathematically represented as
Here is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s
Now
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Generally the distance covered by Henrietta before catching her lunch is
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Generally the speed with which Bruce threw her lunch is mathematically represented as