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cricket20 [7]
3 years ago
5

PLS HELP ASAP Assignment due in 30 min and a LOT more questions

Physics
2 answers:
Anettt [7]3 years ago
8 0
I think the answer is electron
krok68 [10]3 years ago
5 0

Answer:

Electrons

Explanation:

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A car covers a distance of 200m. If its velocity is 20 m/s, calculate the time taken. ​
Anvisha [2.4K]

Answer:

10 seconds

Explanation:

  • velocity=displacement/time
7 0
3 years ago
Atomic theory that states that atoms have three fundamental parts, and that electrons orbit the nucleus:
zhannawk [14.2K]
The <span>Atomic theory that states that atoms have three fundamental parts, and that electrons orbit the nucleus is the kinetic molecular theory of gases.</span>
8 0
3 years ago
A gun with a muzzle velocity of 100 m/s is fired horizontally from a tower. Neglecting air resistance, how far downrange will th
Neporo4naja [7]

Answer:

313.6 m downward

Explanation:

The distance covered by the bullet along the vertical direction can be calculated by using the equation of motion of a projectile along the y-axis.

In fact, we have:

y(t) = h +u_y t + \frac{1}{2}at^2

where

y(t) is the vertical position of the projectile at time t

h is the initial height of the projectile

u_y = 0 is the initial vertical velocity of the projectile, which is zero since the bullet is fired horizontally

t is the time

a = g = -9.8 m/s^2 is the acceleration due to gravity

We can rewrite the equation as

y(t)-h = \frac{1}{2}gt^2

where the term on the left, y(t)-h, represents the vertical displacement of the bullet. Substituting numbers and t = 8 s, we  find

y(t)-h= \frac{1}{2}(-9.8)(8)^2 = -313.6 m

So the bullet has travelled 313.6 m downward.

6 0
4 years ago
A 51.7-kg hiker ascends a 43.2-meter high hill at a constant speed of 1.20 m/s. Determine the work done in climbing the hill.​
iren [92.7K]
W=m/d. w=51.7\1.20 W=43.083333333J
6 0
2 years ago
study a 75kg person stands on a scale in an elevator what does read in n and in kg when the elevator is at rest?
Verdich [7]

To solve this problem we will use Newton's second law in order to obtain the weight of a person. The second law tells us that

F = ma

Where,

m = mass

a = Acceleration

In this particular case, the acceleration is equal to that exerted by the earth through gravitational acceleration, so if the person's weight is 75Kg and the gravity is 9.8m / s^2 , the weight of the body will be,

F_W =mg

F_W = (75kg)(9.8m/s^2 )

F_W = 735.75N

When the elevator is at rest this reads 735.75N and 75Kg (The same mass of the person)

6 0
3 years ago
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