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2 years ago

If cos 0 =8/17, what is sin 0?

Mathematics

1 answer:

ipn [44]2 years ago

3 0

Answer:

sin=15/17

Step-by-step explanation:

Use the definition of sine to find the value of

sin (0)

sin (0) = opp/hyp

THEN

Substitute in the known values.

sin (0) = 15/17

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3 years ago

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BARSIC [14]

I'll abbreviate $s=\sin\theta$ and $c=\cos\theta$ , so the identity to prove is

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On the left side, we can simplify a bit:

$\dfrac{s+c+1}{s+c-1}=\dfrac{s+c-1+2}{s+c-1}=1+\dfrac2{s+c-1}$

$\dfrac{1+s-c}{1-s+c}=-\dfrac{-2+1-s+c}{1-s+c}=-1+\dfrac2{1-s+c}$

Then

$\dfrac{s+c+1}{s+c-1}-\dfrac{1+s-c}{1-s+c}=2\left(1+\dfrac1{s+c-1}-\dfrac1{1-s+c}\right)$

So the establish the original equality, we need to show that

$\dfrac1{s+c-1}-\dfrac1{1-s+c}=\dfrac1s$

Combine the fractions:

$\dfrac{(1-s+c)-(s+c-1)}{(s+c-1)(1-s+c)}=\dfrac{2-2s}{c^2-s^2+2s-1}$

We can rewrite the denominator as

$c^2-s^2+2s-1=c^2+s^2-2s^2+2s-1$

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$1-2s^2+2s-1=2s-2s^2$

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as desired.

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Read 2 more answers

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the correct question in the attached figure

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the probability
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the answer is the option B 0.0000128

There are a variety of problems in which the number of witnesses change, for example
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4 years ago

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Answer:

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Step-by-step explanation:

See pic for more fun.

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