Answer:
B. The current increases.
Explanation:
As we know that rate of flow of charge through the conductor is known as electric current
So we have
here we know that charge Q flowing through the conductor is constant while the time in which it passes through it is decreased
so we can say that the ratio of charge and time will increase
so here we have
So correct answer will be
B. The current increases.
Answer:
153.6 kN
Explanation:
The elastic constant k of the block is
k = E * A/l
k = 95*10^9 * 0.048*0.04/0.25 = 729.6 MN/m
0.12% of the original length is:
0.0012 * 0.25 m = 0.0003 m
Hooke's law:
F = x * k
Where x is the change in length
F = 0.0003 * 729.6*10^6 = 218.88 kN (maximum force admissible by deformation)
The compressive load will generate a stress of
σ = F / A
F = σ * A
F = 80*10^6 * 0.048 * 0.04 = 153.6 kN
The smallest admisible load is 153.6 kN
Total work done is 0.13 Joules
<h3>What is work done ?</h3>
The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force.
According to the given information
We need to find the work done
work done = force × distance
We are given,
force = 26 N
Distance = 0.0005 meter
hence ,
Work done = 26 × 0.005
= 0.13 Joules
Total work done is 0.13 Joules
To know more about Work done
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