We are given with the specific heat capacity of ethanol, the mass of the sample and the temperature change to determine the total amount of heat to raise the temperature. The formula to be followed is H = mCpΔT. Upon subsituting, H = 79 g * 2.42 J/gC *(385-298)C = 16.63 kJ
Answer:
The tension in the rope is 262.88 N
Explanation:
Given:
Weight
N
Length of rope
m
Initial speed of ball 
For finding the tension in the rope,
First find the mass of rod,
(
)

kg
Tension in the rope is,


N
Therefore, the tension in the rope is 262.88 N
Answer:

Explanation:
Given that,
Mass, m = 27 grams
Volume of the substance, V = 15 cm³
We need to find the density of the substance. We know that, the density of an object is given by mass per unit volume. So,

So, the density of the substance is equal to
.